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3 years ago

Plz help me asap plz

SAT

2 answers:

OLEGan [10]3 years ago

7 0

Answer:

a hammer falling off a table

Explanation:

WARRIOR [948]3 years ago

6 0

The answer is c because kinetic energy has to do with an object in motion

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Monster monster Monsteruhhggj answer this

MatroZZZ [7]

Answer:

Wth?

Explanation:

I'm not even being rude

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3 years ago

You are the shift supervisor at a local restaurant. You note that 15 employees work on Sundays. This represents 60% of all

dlinn [17]

Answer:

I got 25 employees total. Proportions was the only way I could think to work it out. I did not get 10 or 20.

Explanation:

1.) 15/x = 60/100

2.) Cross multiply. 15×100

60×x

3.) Divide 60 into 1500 -> x=25

6 0

3 years ago

According to a study conducted by an organization, the proportion of Americans who were afraid to fly in 2006 was 0.10. A rando

Vedmedyk [2.9K]

Explanation:

According to a study conducted by an organization, the proportion of Americans who were afraid to fly in 2006 was 0.10. A random sample of 1,100 Americans results in 121 indicating that they are afraid to fly. Explain why this is not necessarily evidence that the proportion of Americans who are afraid to fly has increased Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. This is not necessarily evidence that the proportion of Americans who are afraid to fly has increased above 0.10 because the sample proportion, is very close to 0.10 (Type an integer or a decimal.) OB. This is not necessarily evidence that the proportion of Americans who are afraid to fly has increased above 0.10 because the probability of obtaining a value equal to or more extreme than the sample proportion is which is not unusual. (Round to four decimal places as needed.) OC. This is not necessarily evidence that the proportion of Americans who are afraid to fly has increased above 0.10 because the value of np(1-P) is less than 10 OD. This is not necessarily evidence that the proportion of Americans who are afraid to fly has increased above 0.10 because the sample size n is more than 5% of the population.

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3 years ago

U.S. Federal Reserve Notes (also referred to as notes or bills) are

jasenka [17]

Answer:

75% 5.8 years

Explanation:

3 0

3 years ago

Match the following functions with functions that exhibit a similar behavior for large values of $x. $.

Delvig [45]

The given polynomials can be rewritten in simplified form by dividing by

a power of the variable of the polynomial.

Responses:

$\dfrac{2 + 3 \cdot x^2 + x^4}{x + 3 \cdot x^3 + x^4}\ \Rightarrow \ \underline{ d. \ 1}$

$\dfrac{5 \cdot x + 2 \cdot x^2 + x^5}{5 \cdot x + 4 \cdot x^2 + x^9} \Rightarrow \underline{a. \ \dfrac{1}{x^4}}$

$\dfrac{7 \cdot x +2}{4 \cdot x + x^3} \Rightarrow \underline{ \ b. \ \dfrac{7}{x^2}}$

$\dfrac{4 + 2 \cdot x^2 }{5 \cdot x + 4 \cdot x^3 + x^5} \Rightarrow \underline{ \ c. \ \dfrac{2}{x^3}}$

<h3>Which method are used to approximate fractional polynomials?</h3>

The possible functions based on a similar question posted online are;

$\dfrac{2 + 3 \cdot x^2 + x^4}{x + 3 \cdot x^3 + x^4}$

$\dfrac{5 \cdot x + 2 \cdot x^2 + x^5}{5 \cdot x + 4 \cdot x^2 + x^9}$

$\dfrac{7 \cdot x +2}{4 \cdot x + x^3}$

$\dfrac{4 + 2 \cdot x^2 }{5 \cdot x + 4 \cdot x^3 + x^5}$

The options are;

$a. \hspace{0.15 cm}\dfrac{1}{x^4}$ <em />

$b. \hspace{0.15 cm}\dfrac{7}{x^2}$

$c. \hspace{0.15 cm}\dfrac{2}{x^3}$

d. 1

$\mathbf{\dfrac{2 + 3 \cdot x^2 + x^4}{x + 3 \cdot x^3 + x^4}}$

$\mathbf{\dfrac{\frac{2}{ x^4}+\frac{x 3 \cdot x^2}{ x^4} + \frac{ x^4}{ x^4} }{\frac{x}{ x^4} + \frac{3 \cdot x^3 }{x^4} +\frac{x^4}{x^4} } }\approx \dfrac{0 + 0 + 1}{0 + 0 + 1} \approx 1$

Therefore;

$The \ match \ for \ \dfrac{2 + 3 \cdot x^2 + x^4}{x + 3 \cdot x^3 + x^4}\ is \ d. \ 1$

$\mathbf{\dfrac{5 \cdot x + 2 \cdot x^2 + x^5}{5 \cdot x + 4 \cdot x^2 + x^9}}$

$\dfrac{5 \cdot x + 2 \cdot x^2 + x^5}{5 \cdot x + 4 \cdot x^2 + x^9} = \mathbf{ \dfrac{\frac{5 \cdot x}{x^5} + \frac{2 \cdot x^2}{x^5} +\frac{x^5}{x^5} }{\frac{5 \cdot x}{x^5} + \frac{4 \cdot x^2}{x^5} + \frac{x^9}{x^5} }} \approx \dfrac{0 + 0 + 1}{0 + 0 + x^4} \approx \dfrac{1}{x^4}$

$The \ match \ for \ \dfrac{5 \cdot x + 2 \cdot x^2 + x^5}{5 \cdot x + 4 \cdot x^2 + x^9} \ is \ a. \ \dfrac{1}{x^4}$

$\mathbf{\dfrac{7 \cdot x +2}{4 \cdot x + x^3}}$

$\dfrac{7 \cdot x +2}{4 \cdot x + x^3} = \dfrac{7 \cdot x }{4 \cdot x + x^3}+ \dfrac{ 2}{4 \cdot x + x^3} = \mathbf{ \dfrac{7 }{4 + x^2}+ \dfrac{ 2}{4 \cdot x + x^3}} \approx \dfrac{7}{x^2}$

Therefore;

$The \ match \ for \ \dfrac{7 \cdot x +2}{4 \cdot x + x^3} \ is \ b. \ \dfrac{7}{x^2}$

$\mathbf{\dfrac{4 + 2 \cdot x^2 }{5 \cdot x + 4 \cdot x^3 + x^5}}$

$\dfrac{4 + 2 \cdot x^2 }{5 \cdot x + 4 \cdot x^3 + x^5} =\mathbf{ \dfrac{\frac{4}{x^2} + \frac{2 \cdot x^2 }{x^2} }{\frac{5 \cdot x}{x^2} + \frac{4 \cdot x^3}{x^2} +\frac{x^5}{x^2}}} \approx \dfrac{0 +2}{0 +4 \cdot x +x^3} \approx \dfrac{2}{x^3}$

$The \ match \ for \ \dfrac{4 + 2 \cdot x^2 }{5 \cdot x + 4 \cdot x^3 + x^5} \ is \ c. \ \dfrac{2}{x^3}$

Learn more about polynomials here:

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6 0

3 years ago