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stepladder [879]
3 years ago
15

Suppose the population of a city is 10,460 in 2006. The population increases at a rate of 5% annually. Approximately how many ye

ars
will it take for the population to double?
A. 13.8 years
B. 14.2 years
C. 15.1 years
D. 15.5 years
Mathematics
1 answer:
professor190 [17]3 years ago
6 0
B is the correct answer your welcome
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Hurry please!
Alexus [3.1K]

Answer:

C. $8483

Step-by-step explanation:

To find the  coffee sales, we plug in the value of x as 34 into y = 60x + 6443.

  • y=60(34)+6443
  • y=2040+6443
  • y=8483

Therefore, the answer is C. $8483.00.

3 0
2 years ago
The measure of the supplement of an angle is three times the measure of the
gtnhenbr [62]
<h2>Answer:</h2>

<h3><em>x=45degrees</em></h3>

<h2>Step-by-step explanation:</h2>

Let the angle to be solved be x

Let the supplement/compliment by y

x+y=90 Complimentary angles add up to 90 degrees.

x+3y=180 Supplementary angles add up to 180 degrees, the other angle is thrice the other compliment.

Evaluating this as a system:

x+y=90 Isolate x:

x=90−y Input into the other equation:

(90−y)+3y=180 Combine like terms, isolate y and its coefficients:

2y=90 Isolate y

y=45 Input into the first equation:

x+45=90 Isolate x:

x=45degrees

5 0
3 years ago
The area of a circle is equal to 1 dm2. Find the radius of the circle.
lisov135 [29]

Answer:

2000

Step-by-step explanation:

1 dm =1000

2dm =?

2dm x 1000

1dm

2000

7 0
2 years ago
Malia measures the longer side of a dollar bill using a ruler at school. Which of the following is most likely the quantity she
sergey [27]

Answer:

6.14 inches

Step-by-step explanation:

The one side of the dollar bill is 6.14 inch. The 6.14 inches of the dollar approximates the 156.1 mm. When Malia measures the longer side of a dollar bill from her rule it will be approximately 6.14 inches in length. The ruler normally has inches and cm sides. Very few rulers have mm scales. The most probable scale that malia would have measure is in inches.

5 0
3 years ago
I need help hdbcjsjfnfnfjfjffdbbfdncndnc
lbvjy [14]
\frac{3}{15k+30} : \frac{6k}{5k^2+30k+40} = \frac{3}{15(k+2)} . \frac{5(k+2)(k+4)}{6k} = \frac{k+4}{6k}
8 0
3 years ago
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