The probability that the spinner lands on an even number or on the unshaded section is; 3/5
<h3>How to find the probability?</h3>
From the spinner attached, we see that the number of sections on the spinner is 5 sections.
Now, we can also see that;
Number of even numbers section = 2
Number of shaded sections = 1
Thus, probability that the spinner lands on an even number or on the unshaded section is;
P(even number or unshaded section) = (2 + 1)/5 = 3/5
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Answer:
=12y+18
Step-by-step explanation:
=(3)(6+4y)
=(3)(6)+(3)(4y)
=18+12y
=12y+18
First bring all terms in 'a' to the left side of the formula by subtracting ac from both sides
ab - ac - cd = ac - ac
ab - ac - cd = 0
now add cd to both sides
ab - ac -cd + cd = cd
ab - ac = cd
now factor the left side by taking out the 'a'
a(b-c) = cd
now divide both sides by (b-c)
a = cd / (b-c)
done
9514 1404 393
Answer:
18 eagles
Step-by-step explanation:
Assuming Julie went bird-watching on each of those 6 days, she saw a total of ...
(3 eagles/day)(6 day) = 3·6 eagles = 18 eagles
To determine which of the choices is lies on the line represented by the equation, 2x + 5y = 4, substitute the values of the abscissas to the x of the equation and solve for y. Evaluate if the y calculated is equal to the ordinate of the ordered pair. Calculations are shown below.
A. (7, -2) ; 2(7) + 5y = 4 ; y = -2 ; EQUAL
B. (0,-1) ; 2(0) + 5y = 4 ; y = 0.8 ; NOT EQUAL
C. (0,1) ; 2(0) + 5y = 4 ; y = 0.8 ; NOT EQUAL
D. (3, -2) ; 2(-3) + 5y = 4 ; y = 2 ; NOT EQUAL
Thus, the answer is letter A. (7, -2)
