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Ratling [72]
3 years ago
8

leroy earns $11.75 per hour working at a coffee shop. on friday, he spent 3 1/2 hours working at the counter, 2 1/2 hours at the

drive through window and 2 hours cleaning. what were leroy's total earnings for friday?
Mathematics
2 answers:
In-s [12.5K]3 years ago
5 0
We can multiply Leroy's hourly wage by the total number of hours he worked. On Friday, Leroy spent a total of (3 1/2 + 2 1/2) hours = 6 hours working. If he earns $11.75 in 1 hour, multiplying this by 6 gives $70.50, so this is the total amount he earned on Friday.
Arturiano [62]3 years ago
5 0
Answer: $94.0

Explanation:

1) The total earnings equal the number of hours worked times the rate per hour:

earnings = numer of hours * rate

2) The rate is $11.75 / h

3) The numbers of hours worked was:

3 \frac{1}{2} +2 \frac{1}{2} +2=3+ \frac{1}{2} +2+ \frac{1}{2} +2=8

4) Final calculation: rate * number of hours

$ 11.75 / h * 8 h = $94.0

Answer: $94.0
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Student performance across discussion sections: A professor who teaches a large introductory statistics class (197 students) wit
adell [148]

Answer:

The test is not significant at 5% level of significance, hence we conclude that there's no variation among the discussion sections.

Step-by-step explanation:

Assumptions:

1. The sampling from the different discussion sections was independent and random.

2. The populations are normal with means and constant variance

H_0: There's no variation among the discussion sections

H_1: There's variation among the discussion sections

\alpha =0.05

                Df     Sum Sq       Mean sq    F value     Pr(>F)

Section     7       525.01         75             1.87            0.99986

Residuals  189    7584.11        40.13

Test Statistic = F= \frac{75}{40.13} =1.87

Pr(>F) = 0.99986

Since our p-value is greater than our level of significance (0.05), we do not reject the null hypothesis and conclude that there's no significant variation among the eight discussion sections.

3 0
3 years ago
(a) Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the prop
zalisa [80]

Answer:

(a) The sample sizes are 6787.

(b) The sample sizes are 6666.

Step-by-step explanation:

(a)

The information provided is:

Confidence level = 98%

MOE = 0.02

n₁ = n₂ = n

\hat p_{1} = \hat p_{2} = \hat p = 0.50\ (\text{Assume})

Compute the sample sizes as follows:

MOE=z_{\alpha/2}\times\sqrt{\frac{2\times\hat p(1-\hat p)}{n}

       n=\frac{2\times\hat p(1-\hat p)\times (z_{\alpha/2})^{2}}{MOE^{2}}

          =\frac{2\times0.50(1-0.50)\times (2.33)^{2}}{0.02^{2}}\\\\=6786.125\\\\\approx 6787

Thus, the sample sizes are 6787.

(b)

Now it is provided that:

\hat p_{1}=0.45\\\hat p_{2}=0.58

Compute the sample size as follows:

MOE=z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})}{n}

       n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}

          =\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666

Thus, the sample sizes are 6666.

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