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lapo4ka [179]
3 years ago
9

the Millers drove 105 miles on 4 gallons of gas. at this rate, how many miles can they drive on 6 gallons of gas.

Mathematics
2 answers:
Masteriza [31]3 years ago
6 0
What she said^^^^^^^^^^^^^
Alinara [238K]3 years ago
5 0

Answer:

157.5 miles with 6 gallons

Step-by-step explanation:

105miles / 4gallons = 26.25miles per gallon

26.25miles per gallon * 6miles = 157.5 miles

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3 years ago
a party of 145people have tea at 22tables at some tables they are 7people and 6of the others how many tables are their 7people
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If all 22 tables had 6 people, there would be 132 people seated. There are 13 more than that, so 13 tables have 7 people.
6 0
3 years ago
ΔABC is dilated by a factor of 3 to produce ΔA'B'C'.
Rus_ich [418]

Answer:

Option B

Step-by-step explanation:

Dilation does not change the value of angle.

so angle measurement should be same as before .

Angle A= 37

Scale factor is 3 so multiply length by 3

So A'C'= 3×5 =15

7 0
2 years ago
Solve a/a-1 - a+5/a =0
sweet [91]
The answer should be 5/a-a=0
4 0
2 years ago
Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be
zheka24 [161]
<h2>Hello!</h2>

The answer is:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

<h2>Why?</h2>

To calculate the speed of the cars, we need to write two equations in order to create a relation between the two speeds and be able to isolate one in function of the other.

So, let be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

x_{FirstCar}=x_o+v*t

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

x_{SecondCar}=x_o+(v+14mph)*t

Now, we already know that both cars met after 2 hours and 45 minutes, meaning that positions will be the same at that moment, and the distance between A and B is 264 miles,  so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph

Then, since we know that they covered a combined distance which is equal to 264 miles of distance in 2 hours + 45 minutes, we  have:

2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours

Writing the equation, we have:

264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph

We have that the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph

Hence, we have that:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

Have a nice day!

4 0
3 years ago
Read 2 more answers
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