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aleksandrvk [35]
3 years ago
8

Please help me with this problem

Mathematics
2 answers:
oee [108]3 years ago
4 0
I think the answer is B. I hope this help.
hoa [83]3 years ago
3 0

Answer:

B

Step-by-step explanation:

Graph the inequality by finding the boundary line, then shading the appropriate area.

y ≥ 2 x − 7

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Yes. 2 squared is irrational number because no two of the same numbers multiplied equals 2. Not including decimals either.
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Let U=[1,23,...,16] C=[1,3,5,...,15] Use the roster method to write the set C'.
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The <em>complement </em>C'<em> </em>of some set C is essentially the set we get when we remove all of the elements of C from the universal set U.

Here, our universal set contains all of the numbers 1-16, and the set C contains all of the odd numbers between 1 and 16. If we were to put both of these sets in roster form:

U=\{1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16\}\\C=\{1,3,5,7,9,11,13,15\}

If we remove all of the elements of C from the universal set U, we're left with the complement of C, which contains all of the <em>even numbers </em>between 1 and 16:

C'=\{2,4,6,8,10,12,14,16\}

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A square with side lengths 12 feet. 4 2 feet by 2 feet squares are cut out of each corner of the square.
ycow [4]
<h3>••••••••••••••••••••••••••••••••••••••••••••••••</h3><h3>\mathbb{PROBLEM:}</h3>

A square with side lengths 12 feet. 4 2 feet by 2 feet squares are cut out of each corner of the square.

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<h3>\mathbb{SOLUTION:}</h3>

  • \bold{A = Length \:  x  \: Width}

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  • \boxed{  \bold{ A = 100.80 ft²}}

"If the 2 is quantity use multiply it again"

<h3>••••••••••••••••••••••••••••••••••••••••••••••••</h3>

<em>NOTE:</em>The way to solve a square area is by measuring the length and width of your area then multiplying those two numbers together to get the area in feet squared (ft2).

"Problem has been solve"

(ノ^_^)ノ

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