Answer:
If (K + 1)^2 = 2n + (n^2)/2, then the answer is Yes, else No.
Step-by-step explanation:
Sum of first K + 1 odd numbers (S): 1 + 3 + 5 + ... + (2K - 3) + (2K - 1) + (2K + 1).
(1 + 3 + 5 + ... + (2K - 3) + (2K - 1) + (2K + 1)) + ((2K + 1) + (2K - 1) + (2K - 3) + ... + 5 + 3 + 1 ) = (2K + 2) + (2K + 2) + (2K + 2) + ... + (2K + 2) + (2K + 2) + (2K + 2) (repeat K + 1 times) = (2K + 2)(K + 1) = 2S
2S = (2K + 2)(K + 1)
S = (2K + 2)(K + 1)/2
S = (2K^2 + 4K + 2)/2
S = K^2 + 2K + 1
S = (K + 1)^2
(4n + n^2)/2 = 2n + (n^2)/2
Answer:
<h2>18</h2>
Step-by-step explanation:
The formula of a distance between two points:

We have the points (5, -7) and (5, 11). Substitute:

Hi again! I'm assuming that the straight line, which I believe is for y = -2 doesn't belong because everything else has two lines, I mean like it reflects off a certain point on the x or y axis but b) [as I like to call it] doesn't reflect on another axis.
Answer:
false- its 4/6
Step-by-step explanation:
Answer:
25
Step-by-step explanation:
a1 = 9
a2 = a1 + 4
a2 = 9 + 4
a2 = 13
a3 = a2 + 4
a3 = 13 + 4
a3 = 17
a4 = 21
a5 = 21 + 4
a5 = 25
This can more easily be done by using this formula
L = a1 + (n - 1) * d
a1 = 9
n = 5
d = 4
L = 9 + (5 -1)*4
L = 9 + 4*4
L = 9 + 16
L = 25