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Rufina [12.5K]
3 years ago
14

Use the graph to find the difference in temperature between 11 A.M. and 1 P.M. ​

Mathematics
2 answers:
MakcuM [25]3 years ago
6 0

Answer:

the tempreture increses

Step-by-step explanation:

swat323 years ago
3 0

Answer:

vshsgshbsbdhhh

Step-by-step explanation:

bsbdhbdbbdbbdbdvvdvvvvdhhdhhdhhdhbdbevdvveh

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On a piece of paper, Graph y
creativ13 [48]
The answer to this question is A
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Which value of m makes this statement true?
melomori [17]
It is number 7, because of that greator or equal to sign, so it has to be 7

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Identify the type of equation: y-6 = 7(x+8)
Ronch [10]

Step-by-step explanation:

Recognize the relation between the graph and the slope–intercept form of an equation of a line

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7 0
3 years ago
Farmer Bill needs 440 yards of fence for a rectangular garden. The length is 30 yards longer than the width. Find the length of
Simora [160]

For this case we have that by definition, the perimeter of a rectangle is given by:

P = 2l + 2w

Where:

l: is the length of the rectangle

w: Is the width of the rectangle

According to the data of the statement we have:

P = 440 \ yards\\l = w + 30

Substituting we have:

440 = 2 (w + 30) + 2w\\440 = 2w + 60 + 2w\\440 = 4w + 60\\440-60 = 4w\\380 = 4w\\w = \frac {380} {4}\\w = 95 \ yards

So the length is:

l = 95 + 30 = 125 \ yards

Answer:

w = 95 \ yards\\l = 95 + 30 = 125 \ yards

6 0
3 years ago
1.Identify and EXPLAIN the ERROR
kondor19780726 [428]

1) The error occurred when you moved the decimal place one spot to the left without changing the exponent of 10 to go along with it.

Not changing the exponent will change the entire value of the answer.  By changing 10.35 to 1.035, we made our answer 10 times smaller, so in order to compensate for that, we need to make 10^10 ten times bigger by changing it to 10^11.

2) 10.35 x 10^10 gets changed to:

1.035 x 10^11


3) The strategy we used is to apply proper scientific notation to our answer.  We should recognize when we drastically change the value of our original answer.

5 0
3 years ago
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