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Mars2501 [29]
3 years ago
11

Rwsfahjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjj

Mathematics
1 answer:
STatiana [176]3 years ago
7 0

Answer:

9 pounds

Step-by-step explanation:

bye good night udjdjri

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Identify the domain and range for the continuous graph provided below. Select all that apply for both the domain and range. Ther
alisha [4.7K]

The answer is 1, 2, 5, and 9

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3 years ago
Please hellpp!!
tino4ka555 [31]

Answer:

the first option

Step-by-step explanation:

d=m/v

must get v alone

(m)d = m/v(m)

on the right side, multiply m/v by m.

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on the left side, multiply d times m.

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An atom has 24 protons and 12 neutrons what is the chemical symbol for the atom?
kykrilka [37]

<u>Answer:</u>

The element is Chromium.

<u>Explanation:</u>

The atom has 24 protons and 12 neutrons.

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Again, we know that the atomic number is the number of protons and the atomic mass is the sum of proton and neutron.

So, the atomic number is 24 and the atomic mass is (24+12)= 36

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3 years ago
The initial size of the population is 300. After 1 day the population has grown to 800. Estimate the population after 6 days. (R
Cloud [144]

Solution :

Given initial population = 300

Final population after 1 day = 800

Number of days = 6

∴ $\frac{dP}{dt} =kt^{1/2} $

P(0) = 300    P(1) = 300

We need to find P(8).

$dP = kt^{1/2} dt$

$ \int 1 dP = \int kt^{1/2} dt$

$P(t) = k \left(\frac{t^{3/2}}{3/2}\right)+c$

$P(t)= \frac{2k}{3}t^{3/2} + c$

When P(0) = 300

$300 = \frac{2k}{3} (0)^{3/2} + c$

∴ c = 300

∴ $P(t)= \frac{2k}{3}t^{3/2} + 300$

When P(1) = 800

$800 = \frac{2k}{3} (1)^{3/2} + 300$

$500 = \frac{2k}{3}$

∴ k = 750

$P(t)= 500t^{3/2} + 300$

So, P(8) is

$P(t)= 500(8)^{3/2} + 300$

        = 11,614

So the population becomes 11,614 after 8 days.

8 0
3 years ago
Two of the angles of a triangle are of measures 30 degree and 35 degree each. The triangle is
Korvikt [17]

The third angle = 180 - 30 - 35 = 115 degrees

so its obtuse

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