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victus00 [196]
3 years ago
6

13. The population of a city is currently 45,000 and is declining at a rate of 2% each year. Estimate the population after a per

iod of 5 years. Use the formula ƒ(t) = aert.
Mathematics
2 answers:
Kazeer [188]3 years ago
8 0

Given:

Initial population = 45,000

Decreasing rate = 2%

Time = 5 year

To find:

The population after a period of 5 years.

Solution:

Formula used:

f(t)=ae^{rt}

where, a is initial population, r is rate and t is time.

r=\dfrac{2}{100}=0.02

Decreasing rate represented by -0.02.

Substitute a=45000, r=-0.02 and t=5 in the above formula.

f(5)=45000e^{-0.02(5)}

f(5)=45000e^{-0.1}

f(5)=45000(0.904837418)

f(5)=40717.68381


Approximate the value to the previous integer.

f(5)\approx 40717


Therefore, the population after 5 years is 40717.

Evgesh-ka [11]3 years ago
5 0

Answer:

40,718

Step-by-step ex

The population of a city is currently 45,000 and is declining at a rate of 2% each year. Estimate the population after a period of 5 years. Use the formula ƒ(t) = aert. planation:

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Setler79 [48]

Answer:

cos(X+Y) = cos(55+35) = cos(90) = 0

Step-by-step explanation:

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3 years ago
What are the answers​
LUCKY_DIMON [66]

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7 0
2 years ago
A scientist conducted an experiment. Due to chemical reaction, the temperature of a compound rose 1/10 degree every 1/4 hour for
klio [65]

Answer:

The rate is \frac{2}{5} degree per hour.

Step-by-step explanation:

Given : A scientist conducted an experiment. Due to chemical reaction, the temperature of a compound rose \frac{1}{10} degree every \frac{1}{4} hour for a limited time.

To find : What was the rate, in degrees per hour that the temperature of the compound rose ?

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puteri [66]
-9h -6 +12h + 40=22\\
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Judges in a diving competition gave scores of 9.3, 9 1/2, 9 4/5, 9.95 And 9 1/4. Which two scores were closest to one another?
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9.3 and 9\frac{1}{4} were closest to another.

<u><em>Explanation</em></u>

First we will convert each given fractions into decimal form. So....

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