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victus00 [196]
3 years ago
6

13. The population of a city is currently 45,000 and is declining at a rate of 2% each year. Estimate the population after a per

iod of 5 years. Use the formula ƒ(t) = aert.
Mathematics
2 answers:
Kazeer [188]3 years ago
8 0

Given:

Initial population = 45,000

Decreasing rate = 2%

Time = 5 year

To find:

The population after a period of 5 years.

Solution:

Formula used:

f(t)=ae^{rt}

where, a is initial population, r is rate and t is time.

r=\dfrac{2}{100}=0.02

Decreasing rate represented by -0.02.

Substitute a=45000, r=-0.02 and t=5 in the above formula.

f(5)=45000e^{-0.02(5)}

f(5)=45000e^{-0.1}

f(5)=45000(0.904837418)

f(5)=40717.68381


Approximate the value to the previous integer.

f(5)\approx 40717


Therefore, the population after 5 years is 40717.

Evgesh-ka [11]3 years ago
5 0

Answer:

40,718

Step-by-step ex

The population of a city is currently 45,000 and is declining at a rate of 2% each year. Estimate the population after a period of 5 years. Use the formula ƒ(t) = aert. planation:

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Answer:

<em>Option C</em>

Step-by-step explanation:

If we were to consider this question as a whole, all we are being asked is to find an expression equivalent to 2 * ( 5 )^x, as all other function are expressed in the same f ( x ) format. Now all we have to thing about are the expression that = 2 * ( 5 )^2x;

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8 0
3 years ago
(Algebra2 HELP please)
Savatey [412]

Maximizing profit, is a way of getting the highest possible profit, from a function.

The bakery should make 45 loaves of A and 0 loaves of B, to maximize profit

To do this, we make use of the following representations.

x represents source A, and y represents source B

So, we have:

<u>Constraint 1: </u>

A uses 5 pounds, and B uses 2 pounds of oats.

Available: 180

The above condition is represented as;

\mathbf{5x + 2y \le 180}

<u>Constraint 2: </u>

A and B use 3 pounds of flour each.

Available: 135

The above condition is represented as;

\mathbf{3x + 3y \le 135}

<u>Objective function</u>

A yields $40, while B yields $30

So, the objective function is:

\mathbf{Maximize\ Z = 40x + 30y}

So, we have:

\mathbf{Maximize\ Z = 40x + 30y}

Subject to

\mathbf{5x + 2y \le 180}

\mathbf{3x + 3y \le 135}

\mathbf{x,y \ge 0}

See attachment for the graph of the subjects

From the graph, we have the corner points to be:

\mathbf{(x,y) = \{(0,45),(30,15),(45,0)\}}

Substitute these values in the objective function

\mathbf{Z = 40(0) +30(45) = 1350}

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\mathbf{Z = 40(45) +30(0) = 1800}

The maximum value of Z is at: (45,0)

This means that: the bakery should make 45 loaves of A and 0 loaves of B, to maximize profit

Read more about maximizing functions at:

brainly.com/question/14728529

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Ben is showing his work in simplifying (3.9 − 9.4) − 0.6 + 6.1. Identify any error in his work or reasoning.
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Should have worked out brackets first then kept it to two subtractions (one being negative number total and the other being positive total number at step  3 ) taking you to step 4 as finish to just add the two numbers a( - 5.3)  + (5.5) = 0.2

Step-by-step explanation:

(3.9 − 9.4) − 0.6 + 6.1.  To simplify do brackets first so the first error was Step 2 line we show (3.9 − 9.4)− 0.6 + 6.1  below = to (-5 .3) − 0.6 + 6.1 Then to simplify Step 3 line there was a second error as 3.9 was never a simplification of the brackets and here is how it should be ( - 5.3)  − 0.6 + 6.1  = ( - 5.3)  + (5.5)  =   ( - 5.3)  + (5.5) Then to simplify Step 4 line we wont need a step 5 and are left to just add the two numbers ( - 5.3)  + (5.5) = 0.2

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