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aalyn [17]
3 years ago
8

DO IT ASAP! Thank you very much!

Mathematics
1 answer:
frozen [14]3 years ago
3 0

Answer:

a = 5

Step-by-step explanation:

According to the factor theorem, if x + 2 is a factor, then by dividing the polynomial by the binomial, we are meant not to have a remainder

In this case, the remainder would be zero

So, if we set the binomial equals zero and substitute the x-value into the polynomial, we are supposed to have 0

So we have this as;

x + 2 = 0

x = -2

-2^3 -2(-2)^2 -2(a) + 6 = 0

-8-8-2a + 6 = 0

-16 + 2a + 6 = 0

2a -10 = 0

2a = 10

a = 10/2

a = 5

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Answer:

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Step-by-step explanation:

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So, because the lengths are not equal,

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The graph of y=√x is shifted 2 units up and 5 units left, Which equation represents the new graph?
Zinaida [17]

y = √(x + 5) + 2

<h3>Further explanation</h3>

<u>Given:</u>

The graph of y = \sqrt{x} is

  • shifted 2 units up, and
  • 5 units left.

<u>Question:</u>

Which equation represents the new graph?

<u>The Process:</u>

The translation is a form of transformation geometry.

Translation (or shifting): moving a graph on an analytic plane without changing its shape.

In general, given the graph of y = f(x) and v > 0, we obtain the graph of:  

  • \boxed{ \ y = f(x) + v \ } by shifting the graph of \boxed{ \ y = f(x) \ } upward v units.  
  • \boxed{ \ y = f(x) - v \ } by shifting the graph of \boxed{ \ y = f(x) \ } downward v units.  

That's the vertical shift, now the horizontal one. Given the graph of y = f(x) and h > 0, we obtain the graph of:  

  • \boxed{ \ y = f(x + h) \ } by shifting the graph of \boxed{ \ y = f(x) \ } to the left h units.  
  • \boxed{ \ y = f(x - h) \ } by shifting the graph of \boxed{ \ y = f(x) \ } to the right h units.

Therefore, the combination of vertical and horizontal shifts is as follows:  

\boxed{\boxed{ \ y = f(x \pm h) \pm v \ }}  

The plus or minus sign follows the direction of the shift, i.e., up-down or left-right.

- - - - - - - - - -

Let's solve the problem.

Initially, the graph of y = \sqrt{x} is shifted 2 units up.

\boxed{y = \sqrt{x} \rightarrow is \ shifted \ 2 \ units \ up \rightarrow \boxed{ \ y = \sqrt{x} + 2 \ }}

Followed by shifting 5 units left.

\boxed{y = \sqrt{x} + 2 \rightarrow is \ shifted \ 5 \ units \ left \rightarrow \boxed{ \ y = \sqrt{x + 5} + 2 \ }}

Thus, the equation that represents the new graph is \boxed{\boxed{ \ y = \sqrt{x + 5} + 2 \ }}

The answer is A.

<h3>Learn more</h3>
  1. Which phrase best describes the translation from the graph y = 2(x – 15)² + 3 to the graph of y = 2(x – 11)² + 3? brainly.com/question/1369568
  2. The similar problem of shifting brainly.com/question/2488474  
  3. What transformations change the graph of (f)x to the graph of g(x)? brainly.com/question/2415963

Keywords: the graph of, y = √x, shifted 2 units up, 5 units left, which, the equation, represents, the new graph, horizontal, vertical, transformation geometry, translation

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