Answer:
When x=4, y=64
Step-by-step explanation:
I'm going to use f(x)=y instead of the letters you have given so the problem would look like f(4)=64. The number in the parentheses, (x), will always be for when x=?. The number on the other side of the = is y=?.
We know that there are 100 cm in 1 m. We can convert 0.75 m to cm by multiplying by 100 to give us:

Therefore the path before the addition is 75 cm wide.
Mr. Kassel added 20 cm of blocks on each side of the path, meaning that the added width is actually 40 cm total (20 on each side, and there are 2 sides).
So we need to add 40 cm to the original 75 cm:

So now we have the width of the path in cm, the question asks for the width in meters. We can do this by dividing the width in cm by 100 to get the width in meters:

Now we know that
the new width of the path is 1.15 m.
Going from 107 to 98 is (minus 9)
going from 98 to 90 is (minus 8)
going from 90 to 83 is (minus 7)
going from 83 to 77 is (minus 6)
following this pattern, the number after 77
is 77 minus 5 = 72
therefore your answer is 72
21+45+70=136
136+(2+x)=180
First subtract 136 from both sides
(2+x)=44=M<ROS
Subtract 2 from both sides
x=42
6x11=66ft
3x14=42ft
Add the answers together
42+66
= 108 squared feet