1)
x^2 + (3y/2z) = 7
2x^2z + 3y = 14z
3y = 14z - 2x^2z
3y = 2z(7 - x^2)
y = 2/3(z)(7 - x^2)
2)
(3zx^4) /(5+z) = 2y
3zx^4 = 2y(5+z)
3zx^4 = 10y + 2yz
Answer: 16 double rooms and 10 single rooms were rented.
Step-by-step explanation:
Let x represent the number of double rooms that were rented.
Let y represent the number of single rooms that were rented.
The total number of rooms rented in a day is 26. It means that
x + y = 26
A motel rents double rooms at $34 per day and single rooms at $26 per day. If all the rooms that were rented for one day cost a total of $804, it means that
34x + 26y = 804 - - - - - - - - - - -1
Substituting x = 26 - y into equation 1, it becomes
34(26 - y) + 26y = 804
884 - 34y + 26y = 804
- 34y + 26y = 804 - 884
- 8y = - 80
y = - 80/ - 8 = 10
x = 26 - y = 26 - 10
x = 16
The expression 30 + 12 can be rewritten as 2x(13+8)
1 foot is shorter that 20 centimeters
Im pretty sure that she has 12 cups.
