
In 1993, Moose Population: 3280
In 1999, population became: 4960
P (Population) , t (years)
t = 6 —> 4960 - 3280 = 1680
Average Change —> 1680/6 = 280 moose/year
• In terms of 1990:
t = 3 —> 3280-3 (280)
P(1990) = 2440
P(t) = 2440 + 280t
• In 2003; t = 13
P(13) = 2440 + 280 (13)
P(13) = 2440 + 3640
P(13) = 6080
• Moose population in 2003
= 6080
Dang this is so hard bro but I think it’s 4
The answer is D
Because if you replace the variables just by testing them they give the answer as X=-3 and Y=3.
In which replacing:
3(-3)+5(3)=6
and with the other equation we've got:
4(-3)+2(3)=-6
so they comply with the required to be the correct answer, even though you can make a system of equation.
Answer: =

Step-by-step explanation:
Answer:
they are ways you can solve for answers like 4 x 4 = 16
Step-by-step explanation: