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3 years ago

Will the given side lengths form a right triangle? 1, 2, 5

Mathematics

1 answer:

jek_recluse [69]3 years ago

3 0

Step-by-step explanation:

For 3 side lengths of a triangle to form a right triangle, the sum of the squares of the 2 smaller side lengths must be equal to the square of the largest side. (a² + b² = c²)

Since 1² + 2² =/= 5², (5 =/= 25)

it will not form a right triangle.

Another Explanation:

Since 5 > 1 + 2, the sum of the 2 smaller side lengths is less than the largest side. Hence it will not form a triangle => not form a right triangle.

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If Lp is a diameter of circle m and , find NO.

Nesterboy [21]

Given that MP is the radius and bisector of QO, then:
QN=NO
hence:
4x-1=2x+3
solving for x
4x-2x=3+1
2x=4
x=2
thus
NO=2x+3=2(2)+3=7

6 0

4 years ago

Read 2 more answers

Find the polynomial of minimum degree, with real coefficients, zeros at x=4+4i and x=2, and y-intercept at 64

Mice21 [21]

Answer:

$\displaystyle -x^3+10x^2-48x+64$

Step-by-step explanation:

We want to find the minimum-degree polynomial with real coefficients and zeros at:

$x= 4+4i\text{ and } x = 2$

As well as a y-intercept of 64.

By the Complex Root Theorem, if a + bi is a root, then a - bi is also a root.

So, a third root will be 4 - 4i.

The factored form of a polynomial is given by:

$P(x)=a(x-p)(x-q)...$

Where a is the leading coefficient and p and q are the zeros. More factors can be added if necessary.

Substitute:

$P(x)=a(x-(2))(x-(4+4i))(x-(4-4i))$

Since we want the minimum degree, we won't need to add any exponents.

Expand the second and third factors:

$\displaystyle \begin{aligned} (x-(4+4i))(x-(4-4i))&=(x-4-4i)(x-4+4i) \\ &= x(x-4-4i)-4(x-4-4i)+4i(x-4-4i)\\ &=x^2-4x-4ix-4x+16+16i+4ix-16i-16i^2\\ &= x^2-8x+32\end{aligned}$

Hence:

$P(x)=a(x-2)(x^2-8x+32)$

Lastly, we need to determine a. Since the y-intercept is y = 64, this means that when x = 0, y = 64. Thus:

$64=a(0-2)(0^2-8(0)+32)$

Solve for a:

$-64a=64\Rightarrow a=-1$

Our factored polynomial is:

$P(x)=-(x-2)(x^2-8x+32)$

Finally, expand:

$\displaystyle \begin{aligned} P(x) &=-(x^2(x-2)-8x(x-2)+32(x-2)) \\&=-(x^3-2x^2-8x^2+16x+32x-64)\\&=-(x^3-10x^2+48x-64)\\&= -x^3+10x^2-48x+64\end{aligned}$

8 0

3 years ago

18 is 0.75% of what number?

LUCKY_DIMON [66]

0.135 is your answer pretty sure.

4 0

3 years ago

The measure I NEED HELP NOW!!!!!!!

Goshia [24]

Answer:

what is the question??

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Please help me with this please and thank you

Ierofanga [76]

Step-by-step explanation:

a geometric sequence means that every term is created by multiplying the previous term by a certain constant factor. this factor is called the "common ratio".

so,

6×r = 18

r = 18/6 = 3

and a quick check tells us this works also for the next terms (18×3 = 54, 54×3 = 162), so it is indeed a geometric sequence with common ratio 3.

a0 = 6

a1 = a0 × 3 = 6×3 = 18

a2 = a1 × 3 = a0 × 3×3 = 6×3² = 54

an = a0 × 3^n = 6 × 3^n

so,

f(x) = 6×3^x, x is integer, x >=0

4 0

3 years ago