Answer:
Following are the solution to this question:
Explanation:
Some of the data is missing in the question, which is defined in the attached file. Please find it.
Follows are the formula which is used in the question:
- EmployeeAnalysis Worksheet IF(C5>49,"Certified","Not Certified")
- Transactions Worksheet IF(F10="No","",0.07)
In the first condition, it checks "C5" is greater than 49 if the condition is true, it will give "Certified" otherwise, it will give "Not Certified".
In the second condition, it checks "F10" is equal to "No" if the condition is true, it will give a blank or space otherwise, it will give "0.07".
The answer is really simple. 7 x 7 = 49. 49/49 is 1. I hope this helps
Answer:
The answer is "14".
Explanation:
Let the IP address 
When it borrowed 4 bits
If the borrowed bits are left out then:
The Number of useable host addresses:
Answer:
(b). dependency and hedging.
Explanation:
In the management of risk, four common approaches for reducing risk are;
i. <em>Avoidance</em>: Especially if a risk involved in the management of a resource (or project) poses or presents a negative consequence, the best way to manage the risk simply avoid it by making sure it doesn't happen. This can be by cancelling a project or restructuring it.
ii. <em>Adaptation</em>: Another way of managing the risk associated with a resource (human or non-human resource) is to control the risk either by increasing resilience or reducing vulnerability. This is called adaptation.
iii. <em>Dependency: </em>This means accepting the risk since every project or business has inherently in it some risk associated. Dealing with it might be a way out especially knowing that there might be some experience to be gained in order to tackle similar situation in the future.
iv. <em>Hedging: </em>This means transferring the risk to some other business or organization. An example might be to get an insurance to manage this risk. In this case, the risk is transferred to the insurance company.
Answer:
There's a parking lot that is 600m² big. The lot must be able to hold at least 3 buses and 10 cars.
Each car takes up 6m² and each bus takes up 30m².
However, there can only be 60 vehicles in the lot at any given time.
The cost to park in the lot is $2.50 per day for cars and $7.50 per day for buses. The lot must make at least $75 each day to break even.
What is a possible car to bus ratio that would allow the lot to make profit?
