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adelina 88 [10]
3 years ago
7

Problems 5-9, Find the value of the variable to the nearest tenth of each triangle.

Mathematics
1 answer:
Eva8 [605]3 years ago
8 0

Answer:

35

Step-by-step explanation:

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D

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How many diagonals does a regualt hexagon have?
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Answer: 9 diagonals

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6 0
2 years ago
Can someone help me with questions 1-4
Natalka [10]
1.)
Old Number:35
New Number:45

Now, subract the new number(45) from the old number. (35)

45-35 is 10. Now divide the old number (35) by 10. 
You'll get 3.5. 3.5%, increase is the answer for #1.

2.) Old: s (students)
     New: 36,750

Do 100+5 (Addition because we do not know what the old number is.) 100+5 is 105. Move decimal over twice and you get 1.05. Multiply 36,750 by 1.05.
There were 38,587.5 kids last year.


3.)Since the discount is 15% off, do 100-15=85. Now, move the decimal over from the percent, and that makes that .85. Now multiply 50x.85. You get 42.5, or $42.50. Now the coupon is 10%, So subtract 100-10, giving you 90. Now move the decimal over. .90. Multiply 42.5 (or 42.50) by .90. You get 38.25. You do have enough money.

4.) Subtract 100-15, giving you 85. Move decimal over from percent. .85.
Now you would multiply .85 times k. B should be the answer.

5 0
3 years ago
Read 2 more answers
Through how many radians do the minute hand and the hour hand move between 1:00 p.m. and 1:45 p.m. (on the same day)? ​
timofeeve [1]

Answer:

π/8 radians

Step-by-step explanation:

THIS IS THE COMPLETE QUESTION

In 1 h the minute hand on a clock moves through a complete circle, and the hour hand moves through 1 12 of a circle. Through how many radians do the minute hand and the hour hand move between 1:00 p.m. and 1:45 p.m. (on the same day)?

SOLUTION

✓If the minute hand on a clock moves through complete circle in 1 hour, then it means that it goes through a circle and angle of circle in radians is 2π.

Between 1:00 p.m. and 1:45pm in the same day we have 45 minutes i.e (1.45 pm -1pm)

Within the 1hour minutes, the hand can move with complete cycle of 2π radians

Then At time t= 45minutes

Angle through the circle at 45 minutes= 45/60 ×2π radians

= 3π/2 radians

And if the hour hand goes through a complete cycle 1/12 as told in the question we have 1/2 × 2π radians

For t=45 minutes

Then 1/12 × 2π ×45/60

= π/8 radians

Hence, the minute hand and the hour hand move π/8 radians between 1:00 p.m. and 1:45 p.m.

5 0
3 years ago
The length of a rectangular is 5 centimeters less then it width. The perimeter of the rectangle is 26
Zina [86]

Hi there! :)

<u>Answer:</u>

Length = 4 cm

Width = 9 cm


Step-by-step explanation:

Here's the information we know:

- Perimeter = 26 cm

- Width = x (I just replaced the width by "x" because it's what we are looking for)

- Length = x - 5


Now before we can do anything, you need to know what the formula for the perimeter of a rectangular is:<u> P = (2 × Length) + (2 × Width)</u>

Replace all the information you know in the formula and solve the equation by isolating "x":

P = (2 × Length) + (2 × Width)

26 = ( 2 × (x - 5)) + (<u>2 × x</u>)

Multiply "2" and "x" together → 2 × x = <u>2x</u>

26 = ( <u>2</u>(x - 5)) + 2x

Distribute the "2" to the entire parentheses → 2 × x = <u>2x</u> & 2 × -5 = <u>-10</u>

26 = <u>2x</u> - 10 + <u>2x</u>

Add similar terms together → 2x + 2x = <u>4x</u>

26 = 4x <u>- 10</u>

Add 10 to each side of the equation → 26 + 10 = <u>36</u>

36 = <u>4</u>x

Divide each side of the equation by 4 → 36 ÷ 4 = <u>9</u>

<u>9 = x ⇒ Measure of the width</u>


Since the lenght is 5 centimeter less than the measure of the width, in order to find the measure of the length you'll need to subtract "5" from the measure of the width, which is "9":

9 - 5 = Length rectangle

9 - 5 = <u>4 ⇒ Length rectangle</u>


There you go! I really hope this helped, if there's anything just let me know! :)

4 0
4 years ago
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