Answer: a. 0.6759 b. 0.3752 c. 0.1480
Step-by-step explanation:
Given : The long-distance calls made by the employees of a company are normally distributed with a mean of 6.3 minutes and a standard deviation of 2.2 minutes
i.e.
minutes
minutes
Let x be the long-distance call length.
a. The probability that a call lasts between 5 and 10 minutes will be :-

b. The probability that a call lasts more than 7 minutes. :
![P(X>7)=P(\dfrac{X-\mu}{\sigma}>\dfrac{7-6.3}{2.2})\\\\=P(Z>0.318)\ \ \ \ [z=\dfrac{X-\mu}{\sigma}]\\\\=1-P(Z](https://tex.z-dn.net/?f=P%28X%3E7%29%3DP%28%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%3E%5Cdfrac%7B7-6.3%7D%7B2.2%7D%29%5C%5C%5C%5C%3DP%28Z%3E0.318%29%5C%20%5C%20%5C%20%5C%20%5Bz%3D%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%5D%5C%5C%5C%5C%3D1-P%28Z%3C0.318%29%5C%5C%5C%5C%3D1-0.6248%5C%20%5C%20%5C%20%5C%20%5B%5Ctext%7Bby%20z-table%7D%5D%5C%5C%5C%5C%3D0.3752)
c. The probability that a call lasts more than 4 minutes. :

Answer:
Step-by-step explanation:
Accessories: x
Bike: 4x
Total1: 5x
Total2: 140 dollars.
x + 4x = 140 dollars
5x = 140
x = 28
Accessories: 28
Bike: 112
Answer:
let cp be x
sp= 115x/100 ---(when 15%gain)
sp = 88x/100------(when 12% loss
according to question
115x/100 - 88x/100 = 81
or, (115x-88x)= 8100
or, 27x = 8100
or, x= 8100/27
x = 300
hence cp is RS 300
Answer:
42.40705%
Step-by-step explanation:
(1 - (23/100)^(19/9) = 1 + r/100
0.57593 = 1 + r/100
r = 42.40705%