30,00 watts.
Think of the metric system like this: K H D B D C M
Now. you have kilo at the begining and milli at the end. To transition from left to right you multiply by 10 each time. To transition from right to left, you divide by 10 each time.

8 0

3 years ago

I have no idea!! Please help!!!

Ber [7]

The area of a traingle is $\frac{1}{2}bh$
So we need to know the base and the height
To work out the sides of a right angle triangle we can use a²+b²=c
c is the hypotenuse and a and b are the other sides
Because this triangle is isoceles we know that a and b are the same

a²+b²=c²
a²+a²=c²
2a²=c²
2a²=(x√6)²
2a²=(x√6)(x√6)
2a²=x²+x√6+x√6+6
2a²=x²+x√6+x√6+6
a²= $\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{2}$
a= $\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}$

A= $\frac{1}{2}bh$
A= $\frac{1}{2}a*a$
A= $\frac{1}{2}$ × $\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}$ × $\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}$
A= $\frac{1}{2}$ × $\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{2}$
A= $\frac{x^{2}+x \sqrt{6}+x \sqrt{6}+6 }{4}$