Answer:
The bearing of B from C is 22° counterclockwise
Step-by-step explanation:
∠CAB = 210 - 90 = 120°
Extend a line from A to the west.
drop a perpendicular line from that line to point C.
Let's call the point at the perpendicular point, M.
∠MAC = 180° - 120° = 60° because they are supplementary.
Now we have a right ∠CMA with a known hypotenuse and a known angle.
Solve for MA:
cos 60° = MA/3.8 = 1.9
Solve for MC:
sin 60° = MC/3.8 = 3.29
MB = 1.9 + 6.4 = 8.3
tan ABC = 3.29/8.3 = 21.62°
