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ikadub [295]
4 years ago
6

What type a problem can be. Using the greatest common factor

Mathematics
1 answer:
sergeinik [125]4 years ago
6 0
The word greatest in a word problem tells you to do GCF and the word least in a problem means to use the LCM
You might be interested in
A car is 180 inches long. A truck is 75% longer than the car. How long is the truck? Explain or show your reasoning.
charle [14.2K]

Answer:

315 inches long

Step-by-step explanation:

180 x .75= 135 <--- that is 75% of 180

then add the two numbers

180 + 135

you add them because the original length of the car is 180 inches and the truck is 75% longer.

180 + 135= 315

8 0
4 years ago
Three consecutive even integers have a sum of 18. find the integers ​
natta225 [31]

Answer:

5,6,7

Step-by-step explanation:

x-1+x+x+1=18

3x=18

x=6

5,6,7

5 0
3 years ago
Which of the following could be points on the unit circle?
ipn [44]

Answer:

Points A and C are on the unit circle

Step-by-step explanation:

The unit circle is a circle of radius 1, that is, all the points that are inside the circle have the sum of the squares of its coordinates that are at most 1. Here, we have to test this for each option.

In options B and D, the coordinates 13/7 and 4/3, respectively, means that this sum will be larger than 1, and this points will not be on the unit circle. Now we text for options A and C.

A. ( 5/13, 12/13)

\sqrt{(\frac{5}{13})^2+(\frac{12}{13})^2} = \sqrt{\frac{25}{169}}+\sqrt{\frac{144}{169}} = \sqrt{\frac{169}{169}} = \sqrt{1} = 1

Since the sum of the squares is 1, the point is on the unit circle.

C. (1/3, 2/3)

\sqrt{(\frac{1}{3})^2+(\frac{2}{3})^2} = \sqrt{\frac{1}{9}}+\sqrt{\frac{4}{9}} = \sqrt{\frac{5}{9}}

Since the sum of the squares is less than 1, the point is on the unit circle.

5 0
3 years ago
One hundred times the quantity seven plus nine
Kipish [7]
100(7 + 9) = 
100(16) =
1600 <=
4 0
3 years ago
39 points no question​
DaniilM [7]

Answer:

Ohhh ok No problem i will accept it

6 0
3 years ago
Read 2 more answers
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