Answer:
#1: Josue's dogs
#2: see images
#3: Am group median: 25.5 Pm group median: 19
#4: Am group first Quartile = 16 Pm group first Quartile = 10
#5: Am group third Quartile = 30 Pm group third Quartile = 37
#6: see images
#7: Am group Interquartile Range = 14 Pm group Interquartile Range = 27
#8: Am group because its Interquartile gruop is smaller than the Pm group
Step-by-step explanation:
Mark as Brainliest
Answer:
First choice.
Step-by-step explanation:
You could plug in the choices to see which would make all the 3 equations true.
Let's start with (x=2,y=-6,z=1):
2x+y-z=-3
2(2)+-6-1=-3
4-6-1=-3
-2-1=-3
-3=-3 is true so the first choice satisfies the first equation.
5x-2y+2z=24
5(2)-2(-6)+2(1)=24
10+12+2=24
24=24 is true so the first choice satisfies the second equation.
3x-z=5
3(2)-1=5
6-1=5
5=5 is true so the first choice satisfies the third equation.
We don't have to go any further since we found the solution.
---------Another way.
Multiply the first equation by 2 and add equation 1 and equation 2 together.
2(2x+y-z=-3)
4x+2y-2z=-6 is the first equation multiplied by 2.
5x-2y+2z=24
----------------------Add the equations together:
9x+0+0=18
9x=18
Divide both sides by 9:
x=18/9
x=2
Using the third equation along with x=2 we can find z.
3x-z=5 with x=2:
3(2)-z=5
6-z=5
Add z on both sides:
6=5+z
Subtract 5 on both sides:
1=z
Now using the first equation along with 2x+y-z=-3 with x=2 and z=1:
2(2)+y-1=-3
4+y-1=-3
3+y=-3
Subtract 3 on both sides:
y=-6
So the solution is (x=2,y=-6,z=1).
Answer:
32
Step-by-step explanation:
XY means x times y
and x = 8 or x is 8
and y = 4 or y is 4
so 4 times 8 is 32
so
XY = 32
Answer:
the graph on the right-top
Step-by-step explanation:
Transferring an "x" to the right side in
, we get 
The system of inequalities is

We have y=2x+2 - ascending function with a=2, b=2
b=2 shows that ascending function intersects Y-axis is in y=2 - that situation is only on the right-top and left-down. So, we refuse left-top and right-down.
y=-x-3 - descending function with a=-1, b=-3
y<2x+2 is an area below the ascending function and we see that on the left-
is an area above the descending function
On the left-down we have an area above both functions, so we refuse this picture
Right-top is correct