Answer:
A.4/7
Step-by-step explanation:
P(A/B) =P(AnB) /P(B)
=1/6/7/24
=1/6×24/7
=4/7
Hey there!
Linear functions have a continuous change.
Let's check these tables and see if we can tell linear functions from non-linear functions.
The first one is
- we add 1 each time
- we subtract 3 each time

Let's try the next one:
- we add 1 each time
- we add 5 each time

Let's try the third one:
- x values: -1, 0, 1, 2
- - we add 1 each time
- we add 3, then 2, then 1..
So this table doesn't represent a linear function.
Let's check the fourth one:
- we add 1 each time
- we add 1 each time
Thus, Option C is the right option.
Hope everything is clear.
Let me know if you have any questions!
Always remember: Knowledge is power!
Answer:
8 ounces of vinegar
36 ounces of dressing
Step-by-step explanation:
Marco makes his famous salad Jackson by mixing 5 1/4 ounces of olive oil with 1 1/2 ounces of vinegar.
Olive oil Vinegar
5 1/4 1 1/2
28 x
Write a proportion:
![\dfrac{5\frac{1}{4}}{28}=\dfrac{1\frac{1}{2}}{x}\\ \\5\dfrac{1}{4}\cdot x=28\cdot 1\dfrac{1}{2}\ [\text{Cross multiply}]\\ \\\dfrac{21}{4}x=28\cdot \dfrac{3}{2}\\ \\\dfrac{21 x}{4}=42\\ \\x=42\div \dfrac{21}{4}\\ \\x=42\cdot \dfrac{4}{21}\\ \\x=2\cdot 4\\ \\x=8\ ounces](https://tex.z-dn.net/?f=%5Cdfrac%7B5%5Cfrac%7B1%7D%7B4%7D%7D%7B28%7D%3D%5Cdfrac%7B1%5Cfrac%7B1%7D%7B2%7D%7D%7Bx%7D%5C%5C%20%5C%5C5%5Cdfrac%7B1%7D%7B4%7D%5Ccdot%20x%3D28%5Ccdot%201%5Cdfrac%7B1%7D%7B2%7D%5C%20%5B%5Ctext%7BCross%20multiply%7D%5D%5C%5C%20%5C%5C%5Cdfrac%7B21%7D%7B4%7Dx%3D28%5Ccdot%20%5Cdfrac%7B3%7D%7B2%7D%5C%5C%20%5C%5C%5Cdfrac%7B21%20x%7D%7B4%7D%3D42%5C%5C%20%5C%5Cx%3D42%5Cdiv%20%5Cdfrac%7B21%7D%7B4%7D%5C%5C%20%5C%5Cx%3D42%5Ccdot%20%5Cdfrac%7B4%7D%7B21%7D%5C%5C%20%5C%5Cx%3D2%5Ccdot%204%5C%5C%20%5C%5Cx%3D8%5C%20ounces)
Marco will make
ounces of dressing
Answer:
The most correct option for the recursive expression of the geometric sequence is;
4. t₁ = 7 and tₙ = 2·tₙ₋₁, for n > 2
Step-by-step explanation:
The general form for the nth term of a geometric sequence, aₙ is given as follows;
aₙ = a₁·r⁽ⁿ⁻¹⁾
Where;
a₁ = The first term
r = The common ratio
n = The number of terms
The given geometric sequence is 7, 14, 28, 56, 112
The common ratio, r = 14/7 = 25/14 = 56/58 = 112/56 = 2
r = 2
Let, 't₁', represent the first term of the geometric sequence
Therefore, the nth term of the geometric sequence is presented as follows;
tₙ = t₁·r⁽ⁿ⁻¹⁾ = t₁·2⁽ⁿ⁻¹⁾
tₙ = t₁·2⁽ⁿ⁻¹⁾ = 2·t₁2⁽ⁿ⁻²⁾ = 2·tₙ₋₁
∴ tₙ = 2·tₙ₋₁, for n ≥ 2
Therefore, we have;
t₁ = 7 and tₙ = 2·tₙ₋₁, for n ≥ 2.