The right answer is -2/3
please see the attached picture for full solution
Hope it helps..
Good luck on your assignment..
P. o. symm is at (-3, -1) it is the center of the circle.
This is what the graph would look like. Hope this helps:)
The first solution is quadratic, so its derivative y' on the left side is linear. But the right side would be a polynomial of degree greater than 1, so this is not the correct choice.
The third solution has a similar issue. The derivative of √(x² + 1) will be another expression involving √(x² + 1) on the left side, yet on the right we have y² = x² + 1, so that the entire right side is a polynomial. But polynomials are free of rational powers, so this solution can't work.
This leaves us with the second choice. Recall that
1 + tan²(x) = sec²(x)
and the derivative of tangent,
(tan(x))' = sec²(x)
Also notice that the ODE contains 1 + y². Now, if y = tan(x³/3 + 2), then
y' = sec²(x³/3 + 2) • x²
and substituting y and y' into the ODE gives
sec²(x³/3 + 2) • x² = x² (1 + tan²(x³/3 + 2))
x² sec²(x³/3 + 2) = x² sec²(x³/3 + 2)
which is an identity.
So the solution is y = tan(x³/3 + 2).
Answer:
distance is 14.04
Step-by-step explanation:
the distance between 2 points is the Hypotenuse of the right angled triangle of the x and y coordinate differences.
we use Pythagoras
c² = a² + b²
c = the Hypotenuse (the side of the triangle opposite to the 90 degree angle).
the x difference
-8 - 6 = -14
the y difference
-2 - -1 = -1
c² = -14² + -1² = 196 + 1 = 197
c = sqrt(197) = 14.04
