First of all, this is not an observational study, but an experiment, since we have two groups and one of the two groups is manipulated or treated. In an observational study the subjects are only observed.
Second, the students did not choose their groups - so we can't choose the last answer.
Therefore the correct answer is:
This is an experiment because a treatment was applied to a group.
False. The image BEFORE it is translated is the pre-image.
An irrational number has an endless decimal. Perfect Squares are rational numbers.
Answer: 39.308 pounds
Step-by-step explanation:
We assume that the given population is normally distributed.
Given : Significance level : ![\alpha: 1-0.98=0.02](https://tex.z-dn.net/?f=%5Calpha%3A%201-0.98%3D0.02)
Sample size : n= 12, which is small sample (n<30), so we use t-test.
Critical value (by using the t-value table)=![t_{n-1, \alpha/2}=t_{11,0.01}=2.718](https://tex.z-dn.net/?f=t_%7Bn-1%2C%20%5Calpha%2F2%7D%3Dt_%7B11%2C0.01%7D%3D2.718)
Sample mean :
Standard deviation : ![\sigma= 20](https://tex.z-dn.net/?f=%5Csigma%3D%2020)
The lower bound of confidence interval is given by :-
![\overline{x}-t_{(n-1,\alpha/2)}\dfrac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=%5Coverline%7Bx%7D-t_%7B%28n-1%2C%5Calpha%2F2%29%7D%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
i.e. ![55-(2.718)\dfrac{20}{\sqrt{12}}](https://tex.z-dn.net/?f=55-%282.718%29%5Cdfrac%7B20%7D%7B%5Csqrt%7B12%7D%7D)
![=55-15.6923803166\approx55-15.692=39.308](https://tex.z-dn.net/?f=%3D55-15.6923803166%5Capprox55-15.692%3D39.308)
Hence, the lower bound for the 98% confidence interval for the mean yearly sugar consumption= 39.308 pounds
Answer:
I believe the answer is, 11.75.
-Hope this helps!
Step-by-step explanation:
To find the mean, you must add up all your data and divide it by how many people there are. So, all the numbers added together is, 82. Since there are seven kids, you would divide 82 by 7. Which equals, 11.75: (Simplified).