Given :
A point ( 1 ,4 ,5 ).
To Find :
The projection of the point on the xy-plane .
Solution :
Now , to find projection of a point in a plane in a plane we need to replace the coordinate of that remaining axis which is not in the plane .
Here , the plane given is xy-plane . So , remaining axis is z .
So , we replace coordinate of z =0 .
Therefore , the projection of the point ( 1 ,4 ,5 ) on the xy-plane is ( 1 ,4 ,0 ) .
Hence , this is the required solution .
Answer:Isolate the variable by dividing each side by factors that don't contain the variable.
d=−5
Step-by-step explanation:
Answer:
its the 3rd one
Step-by-step explanation:
Answer:
-14
Step-by-step explanation:
-9=6/v
You have to multiply v both sides because
6/v x v = 6 and helps you get rid of the v on the right side.
If you multiply by 6, 6/v x 6 = 36/v, that’s why it don’t work.
Answer:
-9=6/v
-9v=6
v=-6/9
v=-2/3
