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inna [77]
3 years ago
12

Please Help! A department store sells a par of shoes with a 93% markup. If the store bought the shoes for 105$ then what is the

retail price?
Mathematics
2 answers:
olasank [31]3 years ago
7 0

Answer:

$202.65

Step-by-step explanation:

105 +97.65 = 202.65

Sindrei [870]3 years ago
3 0

Answer:

$202.65

Step-by-step explanation:

If the store is marking up the price in which it bought it then the price should be $202.65 since you are adding the 93% to the original price.

Hope this helps! :)

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Which is the greater fraction<br>3/4 or 11/16​
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Answer:

3/4

Step-by-step explanation:

3/4 = 75%

11/16 = about 68%

Therefore, 3/4 is greater

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3 years ago
Can you please help
Free_Kalibri [48]

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The answer to the question provided is

\frac{9}{5}

Step-by-step explanation:

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Evaluate the following expression when b = -2.4<br><br> 2 x 5x =
Illusion [34]
Are you sure it’s b or is it x?
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Suki makes and sells denim jackets in a small store at the mall. She has found that
Mrrafil [7]

Answer:

8

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6 0
3 years ago
For each of the following scenarios state whether H0 should be rejected or not. State any assumptions that you make beyond the i
scoundrel [369]

Answer:

a)H_0 :\mu = 4\\ H_1 : \mu \neq 4 , n = 15 , X=3.4 , S=1.5 , α = .05

Formula : t = \frac{x-\mu}{\frac{s}{\sqrt{n}}}

t = \frac{3.4-4}{\frac{1.5}{\sqrt{15}}}

t =-1.549

p- value = 0.607(using calculator)

α = .05

p- value > α

So, we failed to reject null hypothesis

b)H_0 :\mu = 21\\ H_1 : \mu < 21 , n =75 , X=20.12 , S=2.1 , α = .10

Formula : t = \frac{x-\mu}{\frac{s}{\sqrt{n}}}

t = \frac{20.12-21}{\frac{2.1}{\sqrt{75}}}

t =-3.6290

p- value = 0.000412(using calculator)

α = .1

p- value< α

So, we reject null hypothesis

(c) H_0 :\mu = 10\\ H_1 : \mu \neq 10, n = 36, p-value = 0.061.

Assume α = .05

p-value = 0.061.

p- value > α

So, we failed to reject null hypothesis

7 0
3 years ago
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