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2 years ago

If the density of a full can is 1.1g/cc what is it’s mass?

Mathematics

1 answer:

podryga [215]2 years ago

6 0

Density = mass / volume
volume of 1 can = 12 * 40 = 480 cm^3
1.1 = mass / 480

mass = 528 grams Answer

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If LP = 15 and PR = 9, find LR. Explain.

Alla [95]

Answer:

LR is 12

Step-by-step explanation:

LP is hypotenuse and PR is base so LR is perpendicular

formula to calculate perpendicular is

p^2=H^2 -b^2

p^2=15^2-9^2

p^2=225-81

p^2=144

p=12(root of 144 is 12)

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3 years ago

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Compare the two investments below. Which will have a greater account balance in the given time periods? Explain.

Doss [256]

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Step-by-step explanation:

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3 years ago

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10. rhombus abcd has vertices at a(-2, 7), b(8, 7), c(2, -1), and d (-8, -1).

horrorfan [7]

Answer: 80

Step-by-step explanation:

We can use the formula $A=\frac{d_{1}d_{2}}{2}$ , where $d_{1}, d_{2}$ are the lengths of the diagonals.

By the distance formula,

$AC=\sqrt{(-2-2)^{2}+(-1-7)^{2}}=\sqrt{16+64}=4\sqrt{5}\\BD=\sqrt{(-8-8)^{2}+(-1-7)^{2}}=\sqrt{256+64}=8\sqrt{5}$

So, the area is $\frac{(4\sqrt{5})(8\sqrt{5})}{2}=\boxed{80}$

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2 years ago

The cost, c(x), for a taxi ride

viva [34]

Answer:

The answer is A.

Go to desmos and type your equation in

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3 years ago

Could someone help me with this ASAP? thanks !

Maru [420]

<h3>Answer:</h3>

A. $6x^2$ +-5x+14x+-35

$6x^2$ +9x-35

B. $5x^4+-3x^3+10x^3+-6x^2$

$5x^4+7x^3-6x^2$

C. $25x^2+-20x+20x+-16$

$25x^2-16$

D. $x^4+-4x^2+-7x^2+28$

$x^4-11x^2+28$

$====================================$

Step-by-step explanation:

A. (3x*2x)+(3x*-5)+(7*2x)+(7*-5)

Multiply and simplify.

$6x^2$ +9x-35

B. ( $x^2*5x^2$ )+( $x^2*$ -3x)+(2x $*5x^2$ )+(2x $*-3x$ )

Multiply and simplify.

$5x^4+7x^3-6x^2$

C. $(5x*5x)+(5x*-4)+(4*5x)+(4*-4)$

Multiply and simplify.

$25x^2-16$

D. $(x^2*x^2)+(x^2*-4)+(-7*x^2)+(-7*-4)$

Multiply and simplify.

$x^4-11x^2+28$

I hope this helps!

But you should really do this yourself.

3 0

3 years ago