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Monica [59]
3 years ago
8

What is the y-intercept of the equation of the line that is perpendicular to the line v= x -x+ 10 and passes through the

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
6 0

Answer:

y=-\frac{5}{3}x+20

Here, m=-5/3, and b=y-intercept=20

Here, the y-intercept is: 20

Thus, option (d) is true.

Step-by-step explanation:

Given the equation

y=\frac{3}{5}x+10

comparing the equation with the slope-intercept form

y=mx+b

Here,

  • m is the slope
  • y is the intercept

so the slope of the line is 3/5.

As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line, so

The slope of the perpendicular line will be: -5/3

Therefore, the point-slope form of the equation of the perpendicular line that goes through (15,-5) is:

y-y_1=m\left(x-x_1\right)

y-\left(-5\right)=\frac{-5}{3}\left(x-15\right)

y+5=\frac{-5}{3}\left(x-15\right)

simplifying the equation to convert it into the slope-intercept form

We know that the slope-intercept form of the line equatio is

y=mx+b

here 'm' is the slope and 'b' is the y-intercept

y+5=\frac{-5}{3}\left(x-15\right)

subtract 5 from both sides

y+5-5=\frac{-5}{3}\left(x-15\right)-5

y=-\frac{5}{3}x+20

Here, m=-5/3, and b=y-intercept=20

Here, the y-intercept is: 20

Thus, option (d) is true.

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