Answer:
Websites
Explanation:
A web server host websites, individuals or corporate websites, this helps us to show our websites in the World Wide Web, there are several companies offers this service, even we can get a free host, but a corporate website or a social media needs a lot of host recourses, these hosts are expensive than other, we could pay a web host monthly or per year.
Answer:
c. Both versions
Explanation:
The Windows Remote management has hardening levels that could be set to Relaxed, Strict, or None based on the channel binding token associated with a request. This feature could be automatically found in the system or manually configured to a user's choice.
Relaxed settings mean rejection of channel binding token that are not valid and the acceptance of requests with no channel binding tokens, but which may be susceptible to attacks. Strict settings entail an automatic rejection of invalid channel binding tokens. None settings entail the acceptance of all requests with no protection against credential-forwarding attacks.
Answer:
There are two ways to print 1 to 1000
- Using Loops.
- Using Recursion.
Explanation:
Using loops
for(int i=1;i<=1000;i++)
{
cout<<i<<" ";
}
Using recursion
Remember you can implement recursion using a function only.
void print(int n)
{
if(n==0)
return;
print(n-1);
cout<<n<<" "';
}
you should pass 1000 as an argument to the function print.
Answer:
To check if the year comes under each 100th year, lets check if the remainder when dividing with 100 is 0 or not.
Similarly check for 400th year and multiple 0f 4. The following C program describes the function.
#include<stdio.h>
#include<stdbool.h>
bool is_leap_year(int year);
void main()
{
int y;
bool b;
printf("Enter the year in yyyy format: e.g. 1999 \n");
scanf("%d", &y); // taking the input year in yyyy format.
b= is_leap_year(y); //calling the function and returning the output to b
if(b==true)
{
printf("Thae given year is a leap year \n");
}
else
{
printf("The given year is not a leap year \n");
}
}
bool is_leap_year(int year)
{
if(year%100==0) //every 100th year
{
if(year%400==0) //every 400th year
{
return true;
}
else
{
return false;
}
}
if(year%4==0) //is a multiple of 4
{
return true;
}
else
{
return false;
}
}
Explanation:
Output is given as image
