Answer: ![\begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:-\frac{2}{3}\quad \mathrm{or}\quad \:x\ge \:0\:\\ \:\mathrm{Decimal:}&\:x\le \:-0.66666\dots \quad \mathrm{or}\quad \:x\ge \:0\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:-\frac{2}{3}]\cup \:[0,\:\infty \:)\end{bmatrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bbmatrix%7D%5Cmathrm%7BSolution%3A%7D%5C%3A%26%5C%3Ax%5Cle%20%5C%3A-%5Cfrac%7B2%7D%7B3%7D%5Cquad%20%5Cmathrm%7Bor%7D%5Cquad%20%5C%3Ax%5Cge%20%5C%3A0%5C%3A%5C%5C%20%5C%3A%5Cmathrm%7BDecimal%3A%7D%26%5C%3Ax%5Cle%20%5C%3A-0.66666%5Cdots%20%5Cquad%20%5Cmathrm%7Bor%7D%5Cquad%20%5C%3Ax%5Cge%20%5C%3A0%5C%5C%20%5C%3A%5Cmathrm%7BInterval%5C%3ANotation%3A%7D%26%5C%3A%28-%5Cinfty%20%5C%3A%2C%5C%3A-%5Cfrac%7B2%7D%7B3%7D%5D%5Ccup%20%5C%3A%5B0%2C%5C%3A%5Cinfty%20%5C%3A%29%5Cend%7Bbmatrix%7D)
Step-by-step explanation:
Answer:
From the graph we can say that ant is moving faster than the ladybug
Slope of the ant's movement will be steeper than the ladybug
- Hence<u>, </u><u>line "</u>v" denotes the speed of ant and <u>line "</u>u" denotes the speed of ladybug.
Unit rate/slope of the graph is (distance traveled/elapsed time)
- <u>Unit rate of ant is 3/2 cm/sec</u> and <u>that of ladybug is 1 cm/sec.</u>
- Ant takes (12×2/3) =<u> </u><u>8</u><u> </u><u>sec</u> and ladybug takes (12×1) =<u> </u><u>12</u><u> </u><u>sec</u> to travel 12 cm.
Remember ant will take less time to travel a certain distance than ladybug.
-9,-8,-7,-6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6,7, in Order from least to greatest
Fudgin [204]
-9,-8,-7,-6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6,7
answer: right
reason: because you are talking about the x axis so if you go left that would be a negative and you cant go up and down bc that's the y axis so the only way to go is right
hope this helped
1. 156
2. 15.6
3. 1.56
You just move the decimal point in depending on the number or zeros.
