Answer: V=8/5 or V=1.6 or V=1 ,3/5 / is over i dont know how the write 8
--
5
on here
Answer:
The slope is 
Step-by-step explanation:
Take the general equation of a straight line 
Here
is the slope of the line.
So let's get the equation of the line in the question in the same form.

Add
to both sides: 
Add
to both sides: 
Divide by
to get it into the general equation: 
Now compare it to the general equation to find the value of
. The value of
is the coefficient of
which we can see is 
Answer
(-3, 3)
Step-by-Step
-3-3/2=-6/2= -3
6-0/2= 6/2 = 3
(-3,3)
Answer:
Minimum 8 at x=0, Maximum value: 24 at x=4
Step-by-step explanation:
Retrieving data from the original question:
![f(x)=x^{2}+8\:over\:[-1,4]](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B2%7D%2B8%5C%3Aover%5C%3A%5B-1%2C4%5D)
1) Calculating the first derivative

2) Now, let's work to find the critical points
Set this
0, belongs to the interval. Plug it in the original function

3) Making a table x, f(x) then compare
x| f(x)
-1 | f(-1)=9
0 | f(0)=8 Minimum
4 | f(4)=24 Maximum
4) The absolute maximum value is 24 at x=4 and the absolute minimum value is 8 at x=0.