If 48 is the new denominator, then..
12 times 4 = 48, so we have to take 7 times 4 as well.
The new numerator would be 28(7 times 4).
Thus, the new fraction would be 28/48. Hope it helps!
Answer:
La suma de cifras del producto original es igual a 12.
Step-by-step explanation:
De acuerdo a la información proporcionada, si multiplicas un número "x" por 32 su resultado sería igual al producto original "y" más 54 dado que dice que se obtiene un producto mayor en 54 al producto original, lo que se puede expresar de la siguiente forma:
32x=y+54
Además, se puede inferir a partir del enunciado que si el número x se hubiera multiplicado por 23 el resultado habría sido el producto original que lo denominamos como "y", por lo que puedes decir que:
y=23x
Ahora puedes reemplazar y=23x en 32x=y+54 y despejar x:
32x=23x+54
32x-23x=54
9x=54
x=54/9
x=6
Finalmente, puedes reemplazar el valor de x en y=23x:
y=23x
y=23*6
y=138
Suma de cifras: 1+3+8 = 12
De acuerdo a esto, la respuesta es que la suma de cifras es igual a 12.
X= 48
this is found by simplifying both sides of the equation , then isolating the variable<span />
Answer:
62.84
Step-by-step explanation:
Volume of both cones is approximately 12.57
formula= pi*r^2*h/3
Volume of the cylinder is approximately 37.7
formula= pi*r^2*h
you add the volumes
12.57+12.57+37.7
= 62.84
Answer: a. 1.981 < μ < 2.18
b. Yes.
Step-by-step explanation:
A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.
First, we calculate mean of the sample:
2.08
Now, we estimate standard deviation:
s = 0.1564
For t-score, we need to determine degree of freedom and 
:
df = 12 - 1
df = 11
= 1 - 0.95
α = 0.05
0.025
Then, t-score is
= 2.201
The interval will be
± 
2.08 ± 
2.08 ± 0.099
The 95% two-sided CI on the mean is 1.981 < μ < 2.18.
B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.
