Question

What is an equation of the line that passes through the points (-4,-3) and (3,-3)

Answer 1

Answer: y=-3

Explanation:

Equation of a line that passes through (a,b) and (c,d) is given by :-

$(y-b)=\dfrac{d-b}{c-a}(x-a)$

The equation of the line that passes through the points (-4,-3) and (3,-3) :

$(y-(-3))=\dfrac{-3-(-3)}{3-(-4)} (x-3)\\\\\Righatrrow\ (y+3)=\dfrac{0}{7}(x-3)\\\\\Rightarrow\ y+3=0\\\\\Rightarrow\ y=-3$

Hence, the equation of the line that passes through the points (-4,-3) and (3,-3) : y=-3