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kondor19780726 [428]
3 years ago
13

Which equation and ordered pair represent the correct vertex form and vertex for j(x) = x2 − 12x + 7?

Mathematics
1 answer:
n200080 [17]3 years ago
6 0
We have the following equation:
 j (x) = x2 - 12x + 7
 We match zero:
 x2 - 12x + 7 = 0
 We pass the constant term to the right:
 x2 - 12x = -7
 We complete square:
 (b / 2) ^ 2 = (-12/2) ^ 2 = (-6) ^ 2 = 36
 x2 - 12x + 36 = -7 + 36
 x2 - 12x + 36 = 29
 The equation in the form of vertex is:
 (x-6) ^ 2 = 29
 The vertice is:
 (6, -29)
 Answer:
 
the correct vertex form is:
 
(x-6) ^ 2 = 29
 
the vertex is:
 
(6, -29)
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SohCahToa

Sin=oposite side/hyptoonuse
Cos=adjacent side/hypotonuse
Tan=oposite side/hypotonuse

oposite side is the side oposite the angle
adjacent side is the side touching the angle that isn't the hypotonuse
hypotonuse is longest side





1.
first solve for hypotonuse using a²+b²=c²
hypotonuse=13
sinA=12/13
cosA=5/13
tanA=12/5
sinB=5/13
cosB=12/13
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2. the missing side is 8
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3. missing side is 25
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