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givi [52]
3 years ago
10

Show all relevant steps.

Mathematics
1 answer:
Usimov [2.4K]3 years ago
7 0
The answer is A hope this helps!
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Simplify all the equations.
hammer [34]

Answer:

C is 5x+13 D is 5x+12

Step-by-step explanation:

expand brackets

8 0
3 years ago
85% of k is 68. What is k?
storchak [24]
If i did my math right, K should equal 80
4 0
3 years ago
Read 2 more answers
Megan wants to build a fence around her pool. The pool is 28 feet long by 23 feet wide. The fence is to be 15 feet from the edge
marshall27 [118]
To determine the amount of fencing needed to enclose the pool area, you will need to add 15 feet to both sides of both dimensions to find the new dimensions that will need enclosed.

28 feet + 15 feet + 15 feet =  58 feet

23 feet + 15 feet + 15 feet = 53 feet

The fence will need to be 2 x 58 + 2 x 53 or 222 feet long for the 53 feet by 58 feet area.

5 0
3 years ago
Find the value of x.<br><br> Please help
bekas [8.4K]

Answer:

86 degrees

Step-by-step explanation:

For triangle the sum of angles is equal to 180 degrees

so,

x+(x-35)+43=180

2x -35+43=180

2x = 180-43+35

2x = 172

x = 86

6 0
3 years ago
Read 2 more answers
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo
muminat

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: {\displaystyle P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}}

Where \lambda is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}

Substitute the respective values in the above formula.

P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})

P(k > 2)= 1 - (0.44596)

P(k > 2)=0.55404

Hence, the required probability is 0.55404.

4 0
3 years ago
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