Question

Help me with this problem please

Answer 1

Answer:

$(a)\ A_1 = s^2$

$(b)\ A_2 = 4s^2$

(c) 4 small squares

Step-by-step explanation:

Given

Small Square:

$Dimension: s$

Large Square:

$Dimension: 2s$ i.e. twice as long as the small square

Solving (a): The area of the small square.

This is calculated as

$Area = Length^2$

So, we have:

$A_1 = s^2$

Solving (b): The area of the large square.

This is calculated as

$Area = Length^2$

So, we have:

$A_2 = (2s)^2$

$A_2 = 4s^2$

Solving (c): Number of small square to cover the large square

To do this, we simply divide their areas.

Let n represents the required number; n is calculated as:

$n = \frac{A_2}{A_1}$

$n = \frac{4s^2}{s^2}$

$n = 4$

Hence, 4 small squares is required to cover the large square