Answer:
The minimum score required for an A grade is 83.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 72.3 and a standard deviation of 8.
This means that 
Find the minimum score required for an A grade.
This is the 100 - 9 = 91th percentile, which is X when Z has a pvalue of 0.91, so X when Z = 1.34.




The minimum score required for an A grade is 83.
Answer:
x+7
Step-by-step explanation:
Answer:
Step-by-step explanation:
40(12/100)
480/100
$4.80
Answer:
if I am right it is 12,600 words
Step-by-step explanation: 90 divided by 3 which is 30 420x30=12,600
Answer:
Y = 6 X=-1
Step-by-step explanation:
- Add the numbers 8x+-8x=0. 5y+y=6y. 22+14=36
- So that means 6y=36. So Y would equal 6
- Substitute the values it one of the original equations. 8x + 5(6) =22. 8x+30=22
- Minus 22 from both sides.
- That would give you 8x=-8
- So x would equal - 1