Answer:
So then the correct answer is B. $200.
Step-by-step explanation:
Notation
Let X be the average contribution size before John makes his contribution.
Let Y be the total contribution size before John makes his contribution.
Let Z be John's contribution.
We know that for this case $ 75 represent the original average amount before the contribution with 50% increase so we can set up the following equation in order to find the original average amount
And solvong for X we got:
Now we can find the total contribution before the donation with the following proportion:
And then with the formula of average taking in count the 6 values we can find the size of donation Z like this:
So then the correct answer is B. $200.
The inequality would be
0.75q ≥ 0.70(q+1)
q is defined as the number of questions he answers after the first one. We are told he gets 75% of those correct; 75%=75/100=0.75. This gives us 0.75q.
Since he gains proficiency on the exercises, the total number he gets correct has to be at least 70%. This means the inequality would have the symbol greater than or equal to, as it cannot be less and have him gain proficiency.
He has already answered 1 question and answers q more; this gives us a total of q+1. Since he gains proficiency, the cutoff was 70%; 70%=70/100=0.70. This gives us the expression 0.70(q+1).
Our total inequality would then be 0.75q ≥ 0.70(q+1)
Substitute the number for the appropriate variables and solve
(ab)^2
(4×3)^2
(12)^2
12×12
144
Your answer is B.144
Answer:
3x + 5y = 11 -> y = -3/5x + 11/5
9x + 15y = 33 -> y = -3/5x + 11/5
Answer:
0,-4
Step-by-step explanation:
the crossing point is on the y-axis the y is always on the rigth (x,y)
