We have two numbers say a, b. And a system of equations.
It looks a bit intimidating but it's actually very easy.
Instead of term a + b in the second equation we can say it's zero because the first equation describes a + b as being equal to 0.
So,
The above equation is not true therefore numbers a and b do not exists in the real number domain.
No solution.
Hope this helps.
In order to easily picture out the operation involving fractions, let's write it in an algebraic equation. So, the above description is written as
20x⁶/15y⁵ × 5y²/6x⁴
The first thing to do is to simplify the easiest terms: the constants. Just multiply all the constants on the numerator and all the constants on the denominator independently. The simplified constant becomes
(20*5)/(15*6) = 10/9
So, the equation to be solved now is
10x⁶y²/9y⁵ x⁴
So, I also multiplied all the variables in the numerator and denominator independently, just like the constants. Then, you apply the laws of exponents. When you divide terms with exponents of the same value of the base, you subtract the exponent on the numerator minus the denominator. It goes like this:
10/9 * x⁶⁻⁴*y²⁻⁵ = 10/9*x²y⁻³
Now, when the exponent as written to the power of a negative exponent, just simply take its reciprocal to make it positive. So, the final answer is
10x²/9y³ or that is letter D.
Attached is a pic of the graph
Answer:
Step-by-step explanation:
t=1.5+0.25m, if t=25 then
1.5+0.25m=25
0.25m=23.5
m=94
So she drove 94 miles.
Three and eight hundredth seventy two thousandth
