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fredd [130]
3 years ago
14

How do i solve 3y = 15x -2

Mathematics
2 answers:
kogti [31]3 years ago
7 0

Answer:

x= y/5 + 2/15

y= 5x- 2/3

Step-by-step explanation:

Solve for both x and y.

If you liked my answer please mark it as brainliest it will be much appreciated.

Thanks! :D

Simora [160]3 years ago
3 0

Answer:

2

Step-by-step explanation:

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topjm [15]

Answer:

A. 1
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7 0
2 years ago
Fill in the table using this function rule y=27-4x
Elis [28]

Step 1: Y= 27 - 4x

To find X - intercept / zero, substitute Y = 0

0 = 27 - 4x

Step 2: 0 = 27 - 4x

Move variable to the left-hand side and change it's sign.

4x = 27

Step 3: 4x = 27

divide both sides of the equation by 4

X = 27/4

solution: X = 27/4

Alternate form: X = 6 3/4, X = 6.75

3 0
3 years ago
Question: Find The Sum Of The Integers From -6 To 58 Of Ss. O 1,500 O 1,734 O 1,690 O 1,621​
REY [17]

Answer:

The Sum Of The Integers From -6 To 58 is <u>1690.</u>

Step-by-step explanation:

Given,

a=-6

T_n=58

We have to find out the sum of integers from -6 To 58.

Firstly we will find out the total number of terms that is 'n'.

Here a_1=-6\ and\ a_2=-5

\therefore d=a_2-a_1=-5-(-6)=-5+6=1

Now we use the formula of A.P.

T_n=a+(n-1)d

On substituting the values, we get;

58=-6+(n-1)1\\\\n-1=58+6\\\\n-1=64\\\\n=64+1=65

So there are 65 terms in between  -6 To 58.

That means we have to find the sum of 65 terms in between  -6 To 58.

Now we use the formula of Sum of n_terms.

S_n=\frac{n}{2}(2a-(n-1)d)

On substituting the values, we get;

S_{65}=\frac{65}{2}(2\times-6+(65-1)1)\\\\S_{65}=\frac{65}{2}(-12+64)\\\\S_{65}=\frac{65}{2}\times52\\\\S_{65}=65\times26=1690

Hence The Sum Of The Integers From -6 To 58 is <u>1690.</u>

5 0
3 years ago
GEOMETRY PROBLEM HELP ME PLEASE
Anon25 [30]

Answer:

18. x=31

19.x=15

20. a. x=5 WXY= 28

b. YXZ=28

c. WXZ=56

6 0
3 years ago
Read 2 more answers
A teacher writes 0.105 on the board. Lisa calls this number "one hundred five thousandths."
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3 years ago
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