The value of the painting in 5 years is $4,320.36
<h3>Expoential functions</h3>
The standard exponential function is expressed as:
Given the following
- P = $3800
- r = 2.6% = 0.026
- t = 5 years
Substitute into the formula
A = 3800(1+0.026)^5
A = 3800(1.026)^5
A = 4,320.36
Hence the value of the painting in 5 years is $4,320.36
Learn more on exponential function here: brainly.com/question/12940982
Answer:
1. 5,400 inches to miles. 5400 in 4. Copage. 12 in. 2. 16 weeks to seconds ... 9. 32 ft/sec to meters/min. 324. 2 in 12.54cm bor mm / 585,22 m/min.) 10. You find ... Directions: Use dimensional analysis to convert each rate. ... Round your answer to the nearest hundredth. 1. ... What is the cyclist's speed in feet per minute?
So if they all add 4 hours to their time then they have:
Jeff 9
Mark 14
Karen 9
Costas 13
Brett 11
Nikki 9
Jack 11
so now to find the mean you add all the numbers together to get 76 and then you divide it by the number of people (7 people) so 76 divided by 7 equals 10.8571429 and that's the mean.
Now to find the median you put all the numbers in order from least to greatest: 9;9;9;11;11;13;14 and you take the number in the middle but since both 11 and 11 are in the middle you take the mean of them and the mean of them is 11 so the median of the numbers is 11
now to find the range you take the largest number (14) and you subtract the smallest number (9) so 14 - 9 is 5 so 5 is the range
and last the mode is the number that is repeated most out of all the numbers so the mode would be 9
Answer:
$15 for a lawn, $105 for seven lawns.
Step-by-step explanation:
The question is about the direct ratio problem. Logically, you will earn more if you mow more lawn.
The scheme for this ratio is given below:
15 n_________n lawns
x_________ 1 lawn
You will earn 15 dollars for mowing a lawn
When you mow 7 lawns, the scheme will be in this manner:
15 n__________n lawns
x__________7 lawns
You will earn 105 dollars
The answer is 12 i have answered a question just like dis disrigard the 1 and the genres just add the total number of cds
