Answer:
x^2 - 11x + 24
Step-by-step explanation:
Foil the equation
x^2 - 3x - 8x + 24
x^2 - 11x + 24
Answer:
4th one
Step-by-step explanation:
must be ![\sqrt[6]{x^{5} }](https://tex.z-dn.net/?f=%5Csqrt%5B6%5D%7Bx%5E%7B5%7D%20%7D)
We use the given data above to calculate the volume of gasoline that is being burned per minute by commercial airplanes.
Amount burned of 1 commercial airplane = <span>3.9 × 10³ ml of gasoline per second
Number of airplanes = </span><span>5.1 × 10³ airplanes
We calculate as follows:
</span> 3.9 × 10³ ml of gasoline per second / 1 airplane (5.1 × 10³ airplanes)(60 second / 1 min ) = <span>1.2 x 10^9 mL / min</span>
Answer:
This means the cost of the item to you is $57.75. You will pay $57.75 for a item with original price of $82.50 when discounted 30%. In this example, if you buy an item at $82.50 with 30% discount, you will pay 82.50 - 24.75 = 57.75 dollars.
Answer:
In a certain Algebra 2 class of 30 students, 22 of them play basketball and 18 of them play baseball. There are 3 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
I know how to calculate the probability of students play both basketball and baseball which is 1330 because 22+18+3=43 and 43−30 will give you the number of students plays both sports.
But how would you find the probability using the formula P(A∩B)=P(A)×p(B)?
Thank you for all of the help.
That formula only works if events A (play basketball) and B (play baseball) are independent, but they are not in this case, since out of the 18 players that play baseball, 13 play basketball, and hence P(A|B)=1318<2230=P(A) (in other words: one who plays basketball is less likely to play basketball as well in comparison to someone who does not play baseball, i.e. playing baseball and playing basketball are negatively (or inversely) correlated)
So: the two events are not independent, and so that formula doesn't work.
Fortunately, a formula that does work (always!) is:
P(A∪B)=P(A)+P(B)−P(A∩B)
Hence:
P(A∩B)=P(A)+P(B)−P(A∪B)=2230+1830−2730=1330
