Answer:
r ≤ -5 and r ≥ 1
Step-by-step explanation:
The solution has two parts:
1) that derived from | 2 +r | ≥ 3 when (2 + r) is already positive. Then:
2 + r ≥ 3, or r ≥ 1
and
that derived from | 2 +r | ≥ 3 when (2 + r) is negative. If (2 + r) is negative, then
|(2 + r)| = -(2 + r) = -2 -r, which is ≥ 3. Therefore, -2 -r ≥ 3, or -r ≥ 5. To solve this for r, divide both sides by -1 and reverse the direction of the inequality sign: r ≤ -5
V(old)=a*b*c
Volume(new)=2a*2b*2c=8abc=8V(old)
volume will increase by 8 times
Answer:
t = infinite amount of solutions
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Step-by-step explanation:
<u>Step 1: Define Equation</u>
2t + 5 = 2t + 5
<u>Step 2: Solve for </u><em><u>t</u></em>
- Subtract 5 on both sides: 2t = 2t
- Divide 2 on both sides: t = t
Here we see that <em>t</em> does indeed equal <em>t</em>.
∴ t = infinite amount of solutions
Answer:
Improper fraction = 19/3
Step-by-step explanation:
To convert to improper fraction;
1.) multiply the denominator with the whole number,
2.) then add the number you got with the numerator (this will be you new numerator)
3.) keep the denominator the same for the new fraction
Hope this helps!
