Complete Question
Suppose the weight of Chipotle burritos follows a normal distribution with mean of 450 grams, and variance of 100 grams2 . Define a random variable to be the weight of a randomly chosen burrito.
(a) What is the probability that a Chipotle burrito weighs less than 445 grams? (3 points)
(b) 20% of Chipotle burritos weigh more than what weight
Answer:
a

b

Step-by-step explanation:
From question we are told that
The population mean is 
The variance is 
The consider weight is 
The standard deviation is mathematically represented as

substituting values


Given that weight of Chipotle burritos follows a normal distribution the the probability that a Chipotle burrito weighs less than x grams is mathematically represented as

Where
is equal to z (the standardized values of the random number X )
So

substituting values


Now from the normal distribution table the value for
is

=> 
Let the probability of the Chipotle burritos weighting more that k be 20% so

=> 
=> 
From the normal distribution table the value of z for
is

=> 
=> 
Due to apparent doubling of numbers in the question, assume
diameter=13 cm/2=0.065m
h=15 cm=0.15m
rho=5.25*1000=5250 kg/m^3
eta=35%=0.35 [efficiency]
t=12 s
g=3.7 m/s^2
mass, m=rho*V=rho*(4pi/3)(r^3)
=5250 kg/m^3 * (4pi/3)(0.065)^3 m^3
=1.922 kg
Work done in lifting h=0.15m
W=mgh
=1.922pi kg * 3.7 m/s^2 * 0.15 m
=1.067pi kg (m/s)^2
=1.067pi J
Average power required, with efficiency eta=0.35
P=(W/t)/eta
=(1.067pi J )/ (12 s) /0.35
=0.254pi J/s
=0.798W (approx.)
Answer:
The value of x is 2
Step-by-step explanation:
<h3><u>Given</u>;</h3>
<h3><u>To Find</u>;</h3>
Now,
tan 27 = 1/x
0.5 = 1/x
x = 1/0.5
x = 2
Thus, The value of x is 2
<u>-TheUnknownScientist 72</u>
1/4 (8x+3) ⇒ 1/4×8x = 2x +3