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chubhunter [2.5K]
3 years ago
15

What is the first step to simplify the expression? (1 Point)

Mathematics
1 answer:
Stells [14]3 years ago
8 0

Multiply first then you would wanna add but you can't until you subtract 5-3 then add I got 12

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Molly was on a long 136 mile road trip. The first part of the trip there was lots of traffic, she only averaged 16 mph. The seco
Mazyrski [523]

Answer:

In traffic, she drove for 3 hours

and After the traffic cleared she drove for 2 hours.

Explanation:

Given that the road trip was 136 miles;

d=136

The first part of the trip there was lots of traffic, she only averaged 16 mph;

v_1=16

The second part of the trip there was no traffic so she could drive 44 mph;

v_2=44

She traveled for a total of 5 hours;

t=5

let x represent the time in traffic when she traveled at 16 mph

t_1=x

the time the traffic is clear would be;

t_2=t-t_1=5-x

Recall that distance equals speed multiply by time;

d=v_1t_1_{}_{}^{}+v_2t_2

substituting the values;

136=16x+44(5-x)

solving for x;

\begin{gathered} 136=16x+220-44x \\ 44x-16x=220-136 \\ 28x=84 \\ x=\frac{84}{28} \\ x=3 \end{gathered}

So;

\begin{gathered} t_1=3\text{ hours} \\ t_2=5-x=5-3=2 \\ t_2=2\text{ hours} \end{gathered}

Therefore, In traffic, she drove for 3 hours

and After the traffic cleared she drove for 2 hours.

7 0
2 years ago
7000 litres of water is pumped out of a tank in 42 minutes. How many litres could be pumped out in one hour at the same rate?
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Answer:

8600 litre×235 will be there in the tanks

7 0
3 years ago
Can some one help me.​
saveliy_v [14]

Answer:

k2j

j=2,k=2

(2)2×(2)

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4 years ago
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Describe the correlation between highway mileage and engine size
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Answer:

As engine size increases, highway mileage decreases.

Step-by-step explanation:

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3 years ago
A square with one side length represented by an expression is shown below
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It is mentioned in the problem that the shape is a square, hence, we could say that all side's measurement is the same and it is equal. It can be written in a different arrangement of terms, but still, the value to be solved is the same. The sides can be written in the following forms:
S1=6(3X+8)+32+12X
S2=18X+48+32+12X
S3=18X+80+12X
S4=30X+80
3 0
3 years ago
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