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chubhunter [2.5K]
3 years ago
15

What is the first step to simplify the expression? (1 Point)

Mathematics
1 answer:
Stells [14]3 years ago
8 0

Multiply first then you would wanna add but you can't until you subtract 5-3 then add I got 12

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A person can pay $8 for a membership to the science museum and then go to the museum for just $1 per visit. What is the maximum
laila [671]

The maximum number of visits for a member of science museum is 36.

Step-by-step explanation:

Given,

Membership fee = $8

Per visit fee = $1

Total cost = $44

Let,

x be the number of visits

y be the total cost

Total cost = per visit fee*number of visits + membership fee

y = x+8

44=x+8\\44-8=x\\36=x\\x=36

The maximum number of visits for a member of science museum is 36.

Keywords: variable, addition

Learn more about variables at:

  • brainly.com/question/12801884
  • brainly.com/question/12817595

#LearnwithBrainly

5 0
3 years ago
How would I solve this question
zvonat [6]

Tan(ANGLE) = Opposite Leg / Adjacent Leg

Tan(60) = Y/8

Y = 8 x tan(60)

Y = 8√3

Y = 13.9

4 0
3 years ago
Read 2 more answers
Suppose that bugs are present in 1% of all computer programs. A computer de-bugging program detects an actual bug with probabili
lawyer [7]

Answer:

(i) The probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

Step-by-step explanation:

Denote the events as follows:

<em>B</em> = bugs are present in a computer program.

<em>D</em> = a de-bugging program detects the bug.

The information provided is:

P(B) =0.01\\P(D|B)=0.99\\P(D|B^{c})=0.02

(i)

The probability that there is a bug in the program given that the de-bugging program has detected the bug is, P (B | D).

The Bayes' theorem states that the conditional probability of an event <em>E </em>given that another event <em>X</em> has already occurred is:

P(E|X)=\frac{P(X|E)P(E)}{P(X|E)P(E)+P(X|E^{c})P(E^{c})}

Use the Bayes' theorem to compute the value of P (B | D) as follows:

P(B|D)=\frac{P(D|B)P(B)}{P(D|B)P(B)+P(D|B^{c})P(B^{c})}=\frac{(0.99\times 0.01)}{(0.99\times 0.01)+(0.02\times (1-0.01))}=0.3333

Thus, the probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii)

The probability that a bug is actually present given that the de-bugging program claims that bug is present is:

P (B|D) = 0.3333

Now it is provided that two tests are performed on the program A.

Both the test are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is:

P (Bugs are actually present | Detects on both test) = P (B|D) × P (B|D)

                                                                                     =0.3333\times 0.3333\\=0.11108889\\\approx 0.1111

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii)

Now it is provided that three tests are performed on the program A.

All the three tests are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is:

P (Bugs are actually present | Detects on all 3 test)

= P (B|D) × P (B|D) × P (B|D)

=0.3333\times 0.3333\times 0.3333\\=0.037025927037\\\approx 0.037

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

4 0
3 years ago
Write and solve an inequality for the following sentence: Jan has saved $50 in her saving account and needs to save at least $26
Juliette [100K]

50 + x ≥ 268

X ≥ 218

STEP BY STEP WORK

50 + x ≥268
-50 -50

x ≥218

Jan needs to save at least $218 for camp


Hope I helped :)
8 0
3 years ago
Dr.hong prescribed 0.019 liter more medicine than dr tannenbaum.dr Evans prescribed 0.02 less than Dr hong who prescribed the mo
dem82 [27]
Dr.hong prescribed the lest and Dr.evans prescribed the most. that is the answer but this is how i got the answer ok so you see that hong gave 0.019 that is not at all the same as 0.02 so you would add a zero to Evans so it would be 0.020 so it is the same length of hongs so now do you know how i got that if not then message me
 <span />
8 0
3 years ago
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