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2 years ago

Pls helphelpepelsjjejdkdkdjf

Mathematics

2 answers:

Yuki888 [10]2 years ago

8 0

Answer:

bbb

Step-by-step explanation:

jonny [76]2 years ago

5 0

I think runner d have a great day

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What is the intersection of the following sets? G = {3, 7, 8, 9} H = {2, 5, 7, 8}

weeeeeb [17]

"The intersection (∩) of a pair of sets (G and H) is a third set (I) composed by the elements that belong, at the same time, to both given sets."

According to this definition:

Given the sets:

G = {3, 7, 8, 9}

H = {2, 5, 7, 8}

The Intersection is:

G ∩ H = I = {7, 8}

:-)

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3 years ago

Read 2 more answers

From experience, it is known that on average 10% of welds performed by a particular welder are defective. if this welder is requ

bulgar [2K]

Binomial distribution can be used because the situation satisfies all the following conditions:1. Number of trials is known and remains constant (n)2. Each trial is Bernoulli (i.e. exactly two possible outcomes) (success/failure)3. Probability is known and remains constant throughout the trials (p)4. All trials are random and independent of the othersThe number of successes, x, is then given by $P(x)=C(n,x)p^x(1-p)^{n-x}$ where $C(n,x)=\frac{n!}{x!(n-x)!}$
Here we're given
p=0.10 [ success = defective ]
n=3

(a) x=0
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,0)0.1^0(1-0.1)^{3-0}$
$=1(1)(0.729)$
$=0.729$

(b) x=2
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,2)0.1^2(1-0.1)^{3-2}$
$=3(0.01)(0.9)$
$=0.027$

(c) x ≥ 2
$P(x)=\sum_{x=2}^3C(n,x)p^x(1-p)^{n-x}$
$=P(2)+P(3)$
$=C(n,2)p^2(1-p)^{n-2}+C(n,3)p^3(1-p)^{n-3}$
$=C(3,2)0.1^2(1-0.1)^{3-2}+C(3,3)0.1^3(1-0.1)^{3-3}$
$=3(0.01)(0.9)+1(0.001)1$
$=0.027+0.001$
$=0.028$

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3 years ago

How many trades of Apple were made

yKpoI14uk [10]

Where the pic or question?

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3 years ago

Multiply and simplify if possible

ad-work [718]

Answer:

6 √ ( 3 x + 5 ) ( 3 x − 2 )

Step-by-step explanation:

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3 years ago

Which of the following functions is not linear?

Marrrta [24]

Answer:

Step-by-step explanation:

The equation of a linear function is in form:

$y=mx+b$

We have:

$\bold{A.}\\\\y=8(x+8)+4(x+8)\qquad\text{use the distributive property}\\\\y=8x+64+4x+32\qquad\text{combine like terms}\\\\y=12x+86\to m=12,\ b=86\\\\\bold{linear\ function}$

$\bold{B.}\\\\y=\dfrac{\sqrt8}{8}x-4\to m=\dfrac{\sqrt8}{8},\ b=-4\\\\\bold{linear\ function}$

$\bold{C.}\\\\y=\dfrac{1}{8}x+8\to m=\dfrac{1}{8},\ b=8\\\\\bold{linear\ function}$

$\bold{D.}\\\\y=8x^2+8x+4\\\\\bold{not\ linear\ function}\\\\\text{because is}\ x^2\\\\\text{It's a quadratic function}$

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3 years ago