Answer:
Step-by-step explanation:
We are given that a and b are rational numbers where
and x is irrational number .
We have to prove a+bx is irrational number by contradiction.
Supposition:let a+bx is a rational number then it can be written in
form
where
where p and q are integers.
Proof:
After dividing p and q by common factor except 1 then we get

r and s are coprime therefore, there is no common factor of r and s except 1.
where r and s are integers.


When we subtract one rational from other rational number then we get again a rational number and we divide one rational by other rational number then we get quotient number which is also rational.
Therefore, the number on the right hand of equal to is rational number but x is a irrational number .A rational number is not equal to an irrational number .Therefore, it is contradict by taking a+bx is a rational number .Hence, a+bx is an irrational number.
Conclusion: a+bx is an irrational number.
Answer:
5,2 = x,y
Step-by-step explanation:
for x go 5 units to the right and for y go 2 units up and there u go
if that did not help then msg (message) this answer or question it.
have a good day.
Answer:
D
Step-by-step explanation:
Answer:
x=-2
Step-by-step explanation:
distribute on both sides
3x+6=4-2x
subtract 2x
5x+6=4
Subtract 6
5x=-10
divide 5 from the x
x=-2