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IrinaVladis [17]

3 years ago

13

Ken and Leah are trying to solve a science homework question they need to find out how much a rock that weighs 5 lb on Earth wit

h ways on Saturn they know they can multiply the amount the rock ways on Earth by 0.93 to find its weight on Saturn

1 answer:

Tomtit [17]3 years ago

3 0

Answer:

Step-by-step explanation:

4.65

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Sam works 5 days a week for 8 hours each day.He earns $8.00 per hour .How much money will he earn after 3 weeks?

kupik [55]

960 dollars because 5 times 3 is 15. 15 times 8 is 120. 120 times 8 is 960

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3 years ago

A bucket holds 6 liters of water. How much is this in ounces? Use the following conversion: 1 liter is 33.8 ounces.

BARSIC [14]

Multiply 6*33.8=202.8

There are 202.8 ounces in a bucket that holds 6 liters

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4 years ago

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If Candler and oteen are 3 1/2 inch apart on the map, what is the actual distance between candler and oteen in miles

anyanavicka [17]

They are 0.00005524 miles apart from each other because 1 in equals 0.00001578 miles

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3 years ago

each side of triangle xyz has length 9 .Find the area of the region inside the circumcircle of the triangle but outside the tria

mote1985 [20]

Answer:

The area of the region inside the circumcircle of the triangle but outside the triangle is

$A=\frac{27}{4}[\pi-3\sqrt{3}]\ units^2$

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the area of triangle

we have an equilateral triangle

Applying the law of sines

$A_t=\frac{1}{2}(b^2)sin(60^o)$

where b is the length side of the equilateral triangle

we have

$b=9\ units$

$A_t=\frac{1}{2}(81)sin(60^o)$

$A_t=\frac{1}{2}(81)\frac{\sqrt{3}}{2}$

$A_t=81\frac{\sqrt{3}}{4}\ units^2$

step 2

Find the area of circle

The area of the circle is equal to

$A_c=\pi r^{2}$

The formula to calculate the radius of the circumcircle of the triangle equilateral is equal to

$r=b\frac{\sqrt{3}}{6}$

where b is the length side of the equilateral triangle

we have

$b=9\ units$

substitute

$r=(9)\frac{\sqrt{3}}{6}$

$r=3\frac{\sqrt{3}}{2}\ units$

Find the area

$A_c=\pi (3\frac{\sqrt{3}}{2})^{2}$

$A_c=\frac{27}{4} \pi\ units^2$

step 3

Find the area of the shaded region

we know that

The area of the region inside the circumcircle of the triangle but outside the triangle is equal to the area pf the circle minus the area of triangle

so

$A=(\frac{27}{4} \pi-81\frac{\sqrt{3}}{4})\ units^2$

Simplify

$A=\frac{27}{4}[\pi-3\sqrt{3}]\ units^2$

6 0

3 years ago

the lengths (in inches) of two sides of a regular pentagon are represented by the expressions 5x-27 and 2x-6. find the length of

fgiga [73]

Since the pentagon is regular, the sides are all of equal length. This tells you

... 5x-27 = 2x-6

... 3x = 21 . . . . . . . add 27-2x

... x = 7

The length of a side can be found by subtituting this value into either expression.

... 2·7-6 = 8 . . . . inches

4 0

3 years ago