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9966 [12]
2 years ago
15

Please help!

Mathematics
1 answer:
Evgen [1.6K]2 years ago
4 0

Answer:

Does this problem have a picture, I just need to make sure I am seeing everything correctly thanks!

Step-by-step explanation:

a. -4 and 4b + 4 = 4b

-4 and 4b + 4 = -4 + (4b + 4) = 4b + (4 - 4) = 4b + 0 = 4b

b. 3x and 1 - 3x = 1

3x and 1 - 3x = 3x + (1 - 3x) = 1 + (3x - 3x) = 1 + 0 = 1

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Answer:

45.50° F

Step-by-step explanation:

As per Newton's law,

T(t) = T_{s}+(T_{0} + T_{s})e^{-kt}

When T(t) is the final temperature

T_{s} = Temperature of surrounding

T_{0} = Initial temperature

t =duration of cooling

k = constant

103=0+(155-0)e^{-k\times 5}

103=155e^{-5k}

Now take natural log on both the sides

ln(103)=ln(155e^{-5k})

ln(103)=ln(155)+ln(e^{-5k})

ln(103)=ln(155)=-5k

4.6347 - 5.0434 = -5k

k=\frac{0.40872}{5}

k = 0.0817

T(t)=0+(155-0)e^{(0.0817\times 15)}

   = 155e^{-1.226}

   = 155 (02935)

  = 45.49 ≈ 45.50° F

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