Decimal. Decimal is the base-10 notational system for representing real numbers. The expression of a number using the decimal system is called its decimal expansion, examples of which include 1, 13, 2028, 12.1, and 3.14159.
Answer:
6 in.
Step-by-step explanation:
Rectangular prism
V = lwh l = 8 W = 3 h = 9
= 8(3)(9)
= 216
Cube
where s = length of side
216 = 
![s = \sqrt[3]{216}](https://tex.z-dn.net/?f=s%20%3D%20%5Csqrt%5B3%5D%7B216%7D)
= 6
Answer:
(a-b) *(a-b) *(a-b)
=(a*a*a) -3*(a*a*b)+3*(a*b*b)-(b*b*b)
34000*(1-7%)*(1-7%)*(1-7%)
=34000*(1-0.07)*(1-0.07)*(1-0.07)
=34000*[(1*1*1)-3*(1*1*0.07)+3*(1*0.07*0.07)-(0.07*0.07*0.07)]
=34000*(1-0.21+0.0147-0.000343)
=34000*(0.804357)
=34*1000*(804.357/1000)
=34*804.357
=<u>27348.138</u>
<u>=</u><u>27348</u>
I:2x – y + z = 7
II:x + 2y – 5z = -1
III:x – y = 6
you can first use III and substitute x or y to eliminate it in I and II (in this case x):
III: x=6+y
-> substitute x in I and II:
I': 2*(6+y)-y+z=7
12+2y-y+z=7
y+z=-5
II':(6+y)+2y-5z=-1
3y+6-5z=-1
3y-5z=-7
then you can subtract II' from 3*I' to eliminate y:
3*I'=3y+3z=-15
3*I'-II':
3y+3z-(3y-5z)=-15-(-7)
8z=-8
z=-1
insert z in II' to calculate y:
3y-5z=-7
3y+5=-7
3y=-12
y=-4
insert y into III to calculate x:
x-(-4)=6
x+4=6
x=2
so the solution is
x=2
y=-4
z=-1
