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2 years ago

Please help me asap. picture is linked

Mathematics

1 answer:

ozzi2 years ago

7 0

Answer:

(4,-2)

Step-by-step explanation:

you just need to move from point P to 5 units to the right and 7 units down

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Factorise the completely 3ax+2ay+6bx+4by

aliina [53]

Answer:

3ax+2ay+6bx+4by

= 3ax+ 6bx+ 2ay + 4by

= 3x(a+2b) +2y(a+2b)

= (3x+2y)(a+2b)

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3 years ago

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There are 1,845 seats in auditorium. The auditorium has 15 sections with the same number of seats in each section. How many seat

Arlecino [84]

1,845 seats in the auditorium divided by the 15 sections will give you 123

There are 123 seats in each section

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3 years ago

What is 5 divided by 9?

kodGreya [7K]

Answer:

0.556

Step-by-step explanation:

such easy math

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2 years ago

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Juan has forty dollars in his jacket. Every day he spends half of the money that is in the

tangare [24]

Answer:

I would say D saturday

Step-by-step explanation:

Hope this helped

4 0

2 years ago

Consider the radical equation (3√6-x)+4=-8. Explain why the calculation in Problem 1 does not produce a solution to the equation

murzikaleks [220]

Answer:

See explanation below

Step-by-step explanation:

<u>First we will solve the radical equation</u> (which I guess was problem 1),

Let's start by simplifying it:

$3\sqrt{6-x}+4=-8\\ 3\sqrt{6-x}=-8-4\\ 3\sqrt{6-x}=-12\\\sqrt{6-x}=-4$

Now we will solve the equation by squaring both sides of the equation:

$\sqrt{6-x} =-4\\6-x=-4^{2} \\6-x=16\\-x=16-6\\-x=10\\x=-10$

So the calculation for x was that x = -10

However, this does not produce a solution to the equation: When we plug this value into the radical equation we get:

$3\sqrt{6-x} +4= -8\\3\sqrt{6-(-10)} +4=-8\\3\sqrt{16}+4 = -8\\ 3(4)+4 = -8\\12 + 4 = -8$

This happens because <u>when we first squared both sides of the equation in the first part of the problem we missed one value for x </u>(remember that all roots have 2 answers, a positive one and a negative one) while squares are always positive.

When we squared the root, we missed one value for x and that is why the calculation does not produce a solution to the equation.

6 0

2 years ago